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Re: how to create a simple elevator simulation? 1 Month Ago by trueframe To make a basic elevator simulation, first, identify the floors and the elevator's capacity. Then, use loops and conditionals in programming to mimic its movement. Include buttons for users to call the elevator and select floors. Test thoroughly for accuracy. Re: Cin Help 12 Years Ago by VernonDozier cin.get() gets one character, not a string. Perhaps you want … better off using the regular old >> operator with cin. cin >> firstword; cin >> secondword; Re: cin.get problems in use 18 Years Ago by Narue cin.get only gets one character. If there are more than … char *msg = "" ) { cout<< msg; cin.ignore ( INT_MAX, '\n' ); cin.get(); } [/code] Of course, that's hackish compared to… Re: Cin question 13 Years Ago by mike_2000_17 …minimize the terminal window and maximize again, this could trigger cin to flush the few letters you had typed before and… OS-specific stuff or a GUI platform of some kind. Cin is meant for command-line instructions: basically, "type …anything to cout and it will never show up in cin because although they share a terminal they are separate … Re: Cin Keyboard inpout to const char* 15 Years Ago by Salem > Cin Keyboard inpout to const char* You want to "INPUT&… Re: cin.getline not working in for loop or...? 18 Years Ago by Narue cin's >> operator and getline don't play well …. Formatted input treats whitespace differently than nonformatted input. More precisely, cin's >> operator leaves a newline character in the… Re: cin.getline not working in for loop or...? 18 Years Ago by Narue >cin.ignore( 2, '\n'); Feel free to replace 2 with any arbitrary number. Someone invariably pipes in with something like this, but fails to do it properly. Once again, search the forum for a better solution. Re: Cin question 13 Years Ago by Ancient Dragon >>cin is a buffer, it needs to flush, just like cout No it is not a buffer -- it is a c++ class. And cin can not be flushed. flush() only works on output streams, never input streams. Re: Cin Fail Method 11 Years Ago by Ancient Dragon cin.fail is not used to keep the screen open -- it is used to simply test to find out if cin succeeded or not. If you want to keep the screen open call cin.get(). Re: cin input 11 Years Ago by Lucaci Andrew `cin` waits till the user inserts something into the stream, and after that it takes into consideration the `'\n'` Re: cin.ignore 15 Years Ago by tymk cin.ignore(this post); Re: cin.ignore 15 Years Ago by Ancient Dragon cin.ignore() does not affect any of the characters in the … Re: cin a two word name 11 Years Ago by Moschops cin >> nameone >> nametwo; cin help 15 Years Ago by acardiac … really these functions work???? 1.cin.ignore() 2.cin.clear() 3.cin.good() 4.cin.fail() 5.cin.bad() 6.cin.eof() I mean to say… Re: cin help 15 Years Ago by rudasi … you enter a different type eg, [code=cplusplus] int number; cin>>number; [/code] if you then enter an integer… enter a character it wont similarily, [code=cplusplus] char initials; cin>>initials; //the ">>" is an… Cin 14 Years Ago by Danny_501 …is: "big St" but this causes the cin /getline function(have tried both) to write it into …. Big st, Little ave):" ;//<< endl; getline (cin, address.street); cout << "Enter suburb:" &…lt;< endl; getline (cin, address.suburb); cout << "Enter state:" <… Cin Help 12 Years Ago by Dasttann777 …, secondword; cout<<"Input: "; firstword = cin.get(); cin.ignore(1,' '); secondword = cin.get(); if (firstword == "print") { secondword = firstword… Re: Cin Help 12 Years Ago by Dasttann777 … string thirdin; int loop = 1; while (loop == 1) { cin >> firstin; cin >> secondin; if (firstin == "print") { cout… firstin)) cout << "Works"; } char q; cin >> q; return 0; } Also How would I do… Re: Cin Help 12 Years Ago by Dasttann777 …; string thirdin; int loop = 1; while (loop == 1) { cin >> firstin; cin >> secondin; if (firstin == "print") { cout…(firstin[i])) cout << "Works"; } char q; cin >> q; return 0; } Thankyou! Re: Cin 14 Years Ago by Danny_501 Never mind lol, I figured it out. I just put cin.ignore() after the problem line and it worked. thanks anyway lol. Re: Cin Help 12 Years Ago by Daxmark …;"; char *car; int loop = 1; while (loop == 1){ getline (cin,word); if (strncmp(word.c_str(),"print",5)==0… Re: Cin Help 12 Years Ago by Daxmark … divword= ""; int loop = 1; while (loop == 1){ getline (cin,word); if (strncmp(word.c_str(),"print",5)==0… Re: Cin Help 12 Years Ago by m4ster_r0shi …;; interpreter_grammar<string::const_iterator> my_grammar; string str; while (getline(cin, str)) { if (str.empty()) break; int expr_type; string::const_iterator iter… Re: Cin help! 12 Years Ago by gerard4143 Line 12. Why are you doing this [code] cin >> calc >> end; [/code] Why >> … <cstdlib> using namespace std; int main () { string calc; cin >> calc; if(calc == "calc") { system("… cin.get() HELP!!! 14 Years Ago by trcartmill … 29 characters whichever comes first. I am trying to use cin.get() to read the name one character at a time… Cin help! 12 Years Ago by Tom_Weston …; using namespace std; int main () { string calc; char end; end = ';'; cin >> calc >> end; if(calc == "calc… cin.getline and cin.ignore problem 13 Years Ago by Meleeruler …project and it worked without having to use the cin.ignore after the specific cout statement. I was obviously… without it it skips the user inputing their data cin.getline(player1Name, NAME_LENGTH); cout<<"How … cout<<"Enter your name: "; cin.ignore(); cin.getline(player2Name, NAME_LENGTH); cout<<"How well… cin.fail() - why it fails after cin.get(...) 16 Years Ago by superjacent …quot;Enter one character: "; cin >> getdata; cin.get(); char line[20]; cout…"\ncin.eof() = false"; if (cin.fail()) cout << "\ncin.fail… false"; // exit routine cin.clear(); while (cin.get() != '\n') continue; cin.get(); return 0; } … Re: cin.fail() - why it fails after cin.get(...) 16 Years Ago by Ancient Dragon …lt;< "Enter one character: "; cin >> getdata; cin.get(); char line[20] = {0}; cout …; << line << "\n"; cin.ignore(); char line2[20] = {0}; cout <<…lt;< "\ncin.eof() = false"; if (cin.fail()) cout << "\ncin.fail() = true&… Re: cin.fail() - why it fails after cin.get(...) 16 Years Ago by Ancient Dragon …lt;< "Enter one character: "; cin >> getdata; cin.get(); char line[20] = {0}; cout …of text 20 characters max: "; cin.getline(line2,20); //cin.ignore(); cout << "\…lt;< "\ncin.eof() = false"; if (cin.fail()) cout << "\ncin.fail() = true&…