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Sep 20th, 2004
Views: 23,215
HI friends!! I am very new to this type of groups, and this is my first post to this group, before asking u all a help I am just posting this code to u all, , please respond for this code
Huffman algorithm is one used for image compression and it is also called as variable length coding, after all u had seen this code, if u have any problems please send me a message.
My code takes a message file(example file is attached with this post as text file) and gives the output.
c Syntax | 4 stars
  1. /*************************/
  2. /*************************/
  3. // HFMANN.C
  4. /*************************/
  5. /*************************/
  6.  
  7. #include<stdio.h>
  8. #include<conio.h>
  9. #include<alloc.h>
  10. #include"C:\windows\desktop\input.h"
  11. #define MAXBITS 32
  12. #define MAXNODES 512
  13. #define MAXSYMBS 256
  14. int hmin(void);
  15. void hinsert(int,int);
  16. struct codetype{
  17. int bits[MAXBITS];
  18. int startpos;
  19. };
  20. struct nodetype{
  21. int freq;
  22. int father;
  23. int isleft;
  24. };
  25. typedef struct hlist{
  26. int pos;
  27. int hfreq;
  28. struct hlist *next;
  29. }hnode;
  30. hnode *hroot=NULL,*traversal;
  31. extern struct list a[256];
  32. extern int n;
  33. int hmin()
  34. {
  35. int p;
  36. p = hroot->pos;
  37. traversal=hroot;
  38. hroot = traversal->next;
  39. free(traversal);
  40. return(p);
  41. }
  42. void hinsert(int p,int freq)
  43. {
  44. hnode* new1=(hnode *)malloc(sizeof(hnode));
  45. new1->pos = p;
  46. new1->hfreq = freq;
  47. traversal = hroot;
  48. if(hroot == NULL)
  49. {
  50. hroot = new1;
  51. hroot->next = NULL;
  52. return;
  53. }
  54. if(hroot->next == NULL)
  55. {
  56. if(hroot->hfreq>new1->hfreq)
  57. {
  58. new1->next = hroot;
  59. hroot =new1;
  60. traversal->next =NULL;
  61. return;
  62. }
  63. else
  64. {
  65. hroot->next =new1;
  66. new1->next =NULL;
  67. return;
  68. }
  69. }
  70. if(hroot->hfreq>=new1->hfreq)
  71. {
  72. new1->next =hroot;
  73. hroot = new1;
  74. return;
  75. }
  76.  
  77. while(traversal->next->hfreq<new1->hfreq)
  78. {
  79. traversal=traversal->next;
  80. if(traversal->next==NULL)
  81. break;
  82. }
  83. if(traversal->next->hfreq>=new1->hfreq)
  84. {
  85. new1->next = traversal->next;
  86. traversal->next = new1;
  87. return;
  88. }
  89.  
  90. new1->next = NULL;
  91. traversal->next = new1;
  92.  
  93. }
  94. int main(){
  95. struct codetype cd,code[MAXSYMBS];
  96. struct nodetype node[MAXNODES];
  97. int i,k,p,p1,p2,root;
  98.  
  99. char symb,alph[MAXSYMBS];
  100. clrscr();
  101. for(i=0;i<MAXSYMBS;i++)
  102. alph[i]=' ';
  103. //scanf("%d",&n);
  104. input();
  105. for(i=0;i<n;i++){
  106. flushall();
  107. // scanf("%c %d",&symb,&node[i].freq);
  108. symb = a[i].alph;
  109. node[i].freq = a[i].freq;
  110. hinsert(i,node[i].freq);
  111.  
  112. alph[i]=symb;
  113. }
  114.  
  115. for(p=n;p<(2*n-1);p++){
  116.  
  117. p1 =hmin();
  118.  
  119. p2 =hmin();
  120.  
  121. node[p1].father = p;
  122. node[p1].isleft = 1;
  123. node[p2].father = p;
  124. node[p2].isleft = 0;
  125. node[p].freq =node[p1].freq+node[p2].freq;
  126. hinsert(p,node[p].freq);
  127. }
  128. root = hmin();
  129. for(i=0;i<n;i++){
  130. cd.startpos = MAXBITS;
  131. p=i;
  132. while(p!=root){
  133. --cd.startpos ;
  134. if(node[p].isleft)
  135. cd.bits[cd.startpos] =0;
  136. else
  137. cd.bits[cd.startpos] =1;
  138. p =node[p].father;
  139. }
  140. for(k=cd.startpos;k<MAXBITS;k++)
  141. code[i].bits[k]=cd.bits[k];
  142. code[i].startpos =cd.startpos;
  143. }
  144. for(i=0;i<n;i++){
  145. printf("\n%c %d",alph[i],node[i].freq);
  146. for(k=code[i].startpos;k<MAXBITS;k++)
  147. printf(" %d",code[i].bits[k]);
  148. printf("\n");
  149. }
  150. return(0);
  151. }
  152.  
  153. /*************************/
  154. /*************************/
  155. // INPUT.H
  156. /*************************/
  157. /*************************/
  158.  
  159.  
  160. #include<stdio.h>
  161. #include<conio.h>
  162. struct list{
  163. char alph;
  164. int freq;
  165. } ;
  166. struct list a[256];
  167. int n;
  168. void input()
  169. {
  170. FILE *fin,*fout;
  171. char *filein,*fileout,ch;
  172. int i,k,f;
  173.  
  174. printf("enter the filename of from which the data is to be read::\n");
  175. scanf("%s",filein);
  176. fin=fopen(filein,"r");
  177. for(i=0,n=0;i<256;i++)
  178. { f=0;k=0;
  179. while((ch=fgetc(fin))!=EOF)
  180. {
  181. if(ch==i)
  182. { f=1;
  183. a[n].alph=ch;
  184. k++;
  185. }
  186. }
  187. if(f==1){
  188. a[n].freq =k;
  189. n++;
  190. }
  191.  
  192. rewind(fin);
  193. }
  194.  
  195.  
  196. fclose(fin);
  197.  
  198. getch();
  199.  
  200. }
  201.  
  202. /*************************/
  203. /*************************/
  204. // message.txt
  205. /*************************/
  206. /*************************/
  207.  
  208. AAAAABBBBACCCCCDDDFGGGGHI
Comments (Newest First)
emil_ham | Newbie Poster | Jan 7th, 2007
man, did you really have to read 255 times from the file, if you could read it once to a buffer and make anything you want with it in main memory. I bet you a fiver it is much cheaper to work with ram than with disk.
bofarull | Newbie Poster | Mar 7th, 2006
To AhmedHan: I bet you a fiver it is the input file called in input.h
AhmedHan | Junior Poster in Training | May 6th, 2005
What is this :#include"C:\windows\desktop\input.h"
Dave Sinkula | long time no c | Jan 28th, 2005
char *filein,*fileout,ch;
scanf("%s",filein);

Yikes!
cscgal | The Queen of DaniWeb | Sep 20th, 2004
I wasn't sure, so I did some research, and found that Huffman's algorithm is an algorithm to form a complete binary tree. The algorithm is shown here http://planetmath.org/encyclopedia/HuffmansAlgorithm.html for those who are interested. Thanks so much for providing us with your code, ckid
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