Yeah, we've been through this. Enough with the overanalyzing and "That's an impossible question" statements. It's just annoying, especially when the question can be answered and agreed upon the same by everyone.
The strength of a classical gravitational field is measured in N kg ^ -1 (Newtons per kilogram). On the surface of the earth this is measured to be about 9.8 N kg ^ -1. Apologies if this has already been said in the thread, but I'm in an internet cafe so in a rush. If no one minds I'll set another question seeing as the last one apparently went a bit "stale":
An imaginary new HD video system (called Purple - Ray) has been launched and the laser it uses to read the disks has a wavelength of 400 nm (4 * 10 ^ -9 m). The lens used has a numerical appature of 1.5. What is the minimum size the markings on the disk (that represent the data) could have and still be resolved by the laser?
Note: numerical aperture is a dimensionless quantity, hence the lack of a unit.
I've always known gravity to be measured in m/s^2. Of course the force of gravity could be 10N but that is completely dependent on the mass of the object that gravity acts on. If you use the equation F = (m1*m2*G)/(d^2) then G isn't measured in newtons or m/s^2. You get (Nm^2)/(kg^2). Unless I did something wrong.
No one has posted to this discussion for at least three months. Please let old threads die and do not reply to them unless you feel you have something new and valuable to contribute that absolutely must be added to make the discussion complete. Otherwise, please start a new thread in this forum instead.