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Views: 1486 | Replies: 48 | Solved
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Join Date: Jan 2008
Posts: 76
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Rep Power: 1
Solved Threads: 1
I'm trying to get this script to work and it is only giving me a blank white page, can someone take a look at it and see if you can tell whats wrong with it.
I must be missing something simple but I just can't find it. This is a form to update a record in a MySQL database.
Thanks.
<?php
// Show simple format of the records so person can choose the reference name/number
// this is then passed to the next page, for all details
$host = "localhost";
$user = "xxx";
$pass = "xxx";
$db = "phonebook";
//Connecting to MYSQL
$connection = mysql_connect($host, $user, $pass) or die ("Unable to connect!");
//Select the database we want to use
mysql_select_db($db) or die ("Could not find database");
// Get all records in all columns from table and put it in $result.
$query = "SELECT * FROM people";
// execute query
$result = mysql_query($query) or die ("Error in query: $query. ".mysql_error());
// Get all records in all columns from table and put it in $result.
$result=mysql_query("select * from people");
/*Split records in $result by table rows and put them in $row.
Make it looping by while statement. */
while($row=mysql_fetch_assoc($result)){
// Output
echo "ID : $row['id'] <br/>";
echo "First Name : $row['fname'] <br/>";
echo "Last Name : $row['lname'] <br/>";
echo "Phone Number : $row['phone_num'] <br/>";
echo "Extension : $row['ext'] <br/>";
echo "Title : $row['title'] <br/>";
echo "Department : $row['dept'] <br/>";
echo "Fax Number : $row['fax'] <hr>";
// Add a link with a parameter(id) and it's value.
echo '<a href="phoneupdate1.php?id='.$row['id'].'">Update</a>';
}
mysql_close();
?>Thanks.
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Join Date: May 2008
Location: Swindon, UK
Posts: 141
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Rep Power: 1
Solved Threads: 22
add this before the while():
This will determine if the query is returning a result
if(mysql_num_rows($result)<1) {
echo 'No Results';
} else {
// while statement here
}This will determine if the query is returning a result
Last edited by xan : May 7th, 2008 at 4:47 pm.
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Join Date: Jan 2008
Posts: 76
Reputation:
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No, still same result. Here is how I put it in:
I thought it looked like it needed one more closing bracket (}) after the echo but that didn't improve anything either.
if(mysql_num_rows($result)<1) {
echo 'No Results';
} else {
// while statement here
while($row=mysql_fetch_assoc($result)){
echo "ID : $row['id'] <br/>";
echo "First Name : $row['fname'] <br/>";
echo "Last Name : $row['lname'] <br/>";
echo "Phone Number : $row['phone_num'] <br/>";
echo "Extension : $row['ext'] <br/>";
echo "Title : $row['title'] <br/>";
echo "Department : $row['dept'] <br/>";
echo "Fax Number : $row['fax'] <hr>";
// Add a link with a parameter(id) and it's value.
echo '<a href="phoneupdate1.php?id='.$row['id'].'">Update</a>';
}
mysql_close();
?>•
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Join Date: May 2008
Location: Swindon, UK
Posts: 141
Reputation:
Rep Power: 1
Solved Threads: 22
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Join Date: May 2008
Location: Swindon, UK
Posts: 141
Reputation:
Rep Power: 1
Solved Threads: 22
•
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Join Date: Jan 2008
Posts: 76
Reputation:
Rep Power: 1
Solved Threads: 1
Yes, all of my other scripts are running just fine.
I took a look at the }'s and agree that it looks like there needs to be one more. I played with adding one but its not making any difference. I think i did have an extra $results in there as well and took that out. Here is what I have now. I've made so many changes now that I don't even remember what I started with
In my while statement, some examples have shown to use fetch_row and some have fetch_assoc, I've got fetch_row in there now. :
This is getting frustrating. If I could get it to display something, i could work with it. The phoneupdate1.php file it is sending to displays fine but needs the info from this page.
All i want to do is be able to change data in my MySQL database if anyone has a more simple way of doing it.
Thanks for all your help guys.
I took a look at the }'s and agree that it looks like there needs to be one more. I played with adding one but its not making any difference. I think i did have an extra $results in there as well and took that out. Here is what I have now. I've made so many changes now that I don't even remember what I started with
In my while statement, some examples have shown to use fetch_row and some have fetch_assoc, I've got fetch_row in there now. :
<?php
error_reporting(E_ALL);
$host = "localhost";
$user = "xxx";
$pass = "xxx";
$db = "phonebook";
//Connecting to MYSQL
$connection = mysql_connect($host, $user, $pass) or die ("Unable to connect!");
//Select the database we want to use
mysql_select_db($db) or die ("Could not find database");
// Get all records in all columns from table and put it in $result.
$query = "SELECT * FROM people ORDER BY fname ASC";
// execute query
$result = mysql_query($query) or die ("Error in query: $query. ".mysql_error());
// Get all records in all columns from table and put it in $result.
if (mysql_num_rows($result) > 0) {
while($row=mysql_fetch_row($result)){
echo "ID : .$row['id'] <br/>";
echo "First Name : $row['fname'] <br/>";
echo "Last Name : $row['lname'] <br/>";
echo "Phone Number : $row['phone_num'] <br/>";
echo "Extension : $row['ext'] <br/>";
echo "Title : $row['title'] <br/>";
echo "Department : $row['dept'] <br/>";
echo "Fax Number : $row['fax'] <hr>";
// Add a link with a parameter(id) and it's value.
echo '<a href="phoneupdate1.php?id='.$row['id'].'">Update</a>';
}
else {
// no
// print status message
echo "No rows found!";
}
}
//mysql_close();
?>All i want to do is be able to change data in my MySQL database if anyone has a more simple way of doing it.
Thanks for all your help guys.
Last edited by rickarro : May 8th, 2008 at 9:36 am.
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Join Date: May 2008
Location: Swindon, UK
Posts: 141
Reputation:
Rep Power: 1
Solved Threads: 22
A couple of problems with your current code:
mysql_fetch_row returns a row in a numerical array, you would need to use $row[0], $row[1] for displaying the data, to use what you are, you will need to use mysql_fetch_assoc to call the cells by the column names.
There is a slight problem here:
You have put it as this:
If {
While {
End While }
Else {}
End If }
It should be:
I'm afraid I cant see any other problems with the actual code, I suggest you also check the database and make sure that the column names are correct (they are case sensitive) and that there is actually data in the table you are using.
mysql_fetch_row returns a row in a numerical array, you would need to use $row[0], $row[1] for displaying the data, to use what you are, you will need to use mysql_fetch_assoc to call the cells by the column names.
There is a slight problem here:
if (mysql_num_rows($result) > 0) {
while($row=mysql_fetch_row($result)){
echo "ID : .$row['id'] <br/>";
echo "First Name : $row['fname'] <br/>";
echo "Last Name : $row['lname'] <br/>";
echo "Phone Number : $row['phone_num'] <br/>";
echo "Extension : $row['ext'] <br/>";
echo "Title : $row['title'] <br/>";
echo "Department : $row['dept'] <br/>";
echo "Fax Number : $row['fax'] <hr>";
// Add a link with a parameter(id) and it's value.
echo '<a href="phoneupdate1.php?id='.$row['id'].'">Update</a>';
}
else {
// no
// print status message
echo "No rows found!";
}
} You have put it as this:
If {
While {
End While }
Else {}
End If }
It should be:
if (mysql_num_rows($result) > 0) {
while($row=mysql_fetch_row($result)){
echo "ID : .$row['id'] <br/>";
echo "First Name : $row['fname'] <br/>";
echo "Last Name : $row['lname'] <br/>";
echo "Phone Number : $row['phone_num'] <br/>";
echo "Extension : $row['ext'] <br/>";
echo "Title : $row['title'] <br/>";
echo "Department : $row['dept'] <br/>";
echo "Fax Number : $row['fax'] <hr>";
// Add a link with a parameter(id) and it's value.
echo '<a href="phoneupdate1.php?id='.$row['id'].'">Update</a>';
}
} else {
// no
// print status message
echo "No rows found!";
} I'm afraid I cant see any other problems with the actual code, I suggest you also check the database and make sure that the column names are correct (they are case sensitive) and that there is actually data in the table you are using.
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Join Date: Jan 2008
Posts: 76
Reputation:
Rep Power: 1
Solved Threads: 1
Ok, you got it there, i changed it to $row and included the row numbers instead of the names and it is now displaying the data I want. Thank you so much.
Here is what I've got now:
This is how it displays with the word "Update" being a link to my update form:
UpdateID : 4
First Name : Edward
Last Name : ScissorHands
Phone Number : xxx-123-456
Extension : 111
Title : Hedgetrimmer
Department : Roads & Grounds
Fax Number :
So far so good, when i click on the update link, it takes me to my update form but does not display the data. Here is what it displays:
Reference:
Last Name :<? echo $row['lname']; ?>
First Name :<? echo $row['fname']; ?>
Phone Number :<? echo $row['phone_num']; ?>
Extension :<? echo $row['ext']; ?>
Title :<? echo $row['title']; ?>
Department :<? echo $row['dept']; ?>
Fax Number :<? echo $row['fax']; ?>
SUBMIT BUTTON
Here is the form it is using:
So now when i use this form does
need to reflect the $row[0] instead of the ['id'] as well? I'm not getting the data from the first form for some reason.
Here is what I've got now:
<?php
error_reporting(E_ALL);
// Show simple format of the records so person can choose the reference name/number
// this is then passed to the next page, for all details
$host = "localhost";
$user = "xxx";
$pass = "xxx";
$db = "phonebook";
//Connecting to MYSQL
$connection = mysql_connect($host, $user, $pass) or die ("Unable to connect!");
//Select the database we want to use
mysql_select_db($db) or die ("Could not find database");
// Get all records in all columns from table and put it in $result.
$query = "SELECT * FROM people ORDER BY fname ASC";
// execute query
$result = mysql_query($query) or die ("Error in query: $query. ".mysql_error());
// Get all records in all columns from table and put it in $result.
if (mysql_num_rows($result) > 0) {
while($row=mysql_fetch_row($result)){
echo "ID : $row[0] <br/>";
echo "First Name : $row[1] <br/>";
echo "Last Name : $row[2] <br/>";
echo "Phone Number : $row[3] <br/>";
echo "Extension : $row[4] <br/>";
echo "Title : $row[5] <br/>";
echo "Department : $row[6] <br/>";
echo "Fax Number : $row[7] <hr>";
// Add a link with a parameter(id) and it's value.
echo '<a href="phoneupdate1.php?id='.$row[0].'">Update</a>';
}
} else {
// no
// print status message
echo "No rows found!";
}
//mysql_close();
?>This is how it displays with the word "Update" being a link to my update form:
UpdateID : 4
First Name : Edward
Last Name : ScissorHands
Phone Number : xxx-123-456
Extension : 111
Title : Hedgetrimmer
Department : Roads & Grounds
Fax Number :
So far so good, when i click on the update link, it takes me to my update form but does not display the data. Here is what it displays:
Reference:
Last Name :<? echo $row['lname']; ?>
First Name :<? echo $row['fname']; ?>
Phone Number :<? echo $row['phone_num']; ?>
Extension :<? echo $row['ext']; ?>
Title :<? echo $row['title']; ?>
Department :<? echo $row['dept']; ?>
Fax Number :<? echo $row['fax']; ?>
SUBMIT BUTTON
Here is the form it is using:
<?php
$record = $_POST['record'];
echo "Reference: $record<br><BR>";
$host = "localhost";
$user = "xxx";
$pass = "xxx";
$db = "phonebook";
//Connecting to MYSQL
MySQL_connect("$host","$user","$pass");
//Select the database we want to use
mysql_select_db($db) or die("Could not find database");
// ***** This part will process when you Click on "Submit" button *****
// Check, if you clicked "Submit" button
if($_POST['Submit']){
// Get parameters from form.
$id=$_POST['id'];
$fname=$_POST['fname'];
$lname=$_POST['lname'];
$phone_num=$_POST['phone_num'];
$ext=$_POST['ext'];
$title=$_POST['title'];
$dept=$_POST['dept'];
// Do update statement.
mysql_query("update phonebook set First Name='$fname', Last Name='$lname', Phone Number='$phone_num', Extension='$ext', Title='$title', Department='$dept' where id='$id'");
// Re-direct this page to select.php.
header("location:phoneupdate.php");
exit;
}
// ************* End update part *************
// *** Select data to show on text fields in form. ***
// Get id parameter (GET method) from select.php
$id=$_POST['id'];
// Get records in all columns from table where column id equal in $id and put it in $result.
$result=mysql_query("select * from people where id='$id'");
// Split records in $result by table rows and put them in $row.
$row=mysql_fetch_assoc($result);
// Close database connection.
mysql_close();
?>
<!-- END OF PHP CODES AND START HTML TAGS -->
<html>
<body>
<!-- set this form to POST method and target this form to itself ($PHP_SELF;)-->
<form id="form1" name="form1" method="post" action="<? echo $PHP_SELF; ?>">
<p>Last Name :
<!-- name of this text field is "Last Name" -->
<input name="lname" type="text" id="lname" value="<? echo $row['lname']; ?>"/>
<br />
First Name :
<!-- name of this text field is "fname" -->
<input name="fname" type="text" id="fname" value="<? echo $row['fname']; ?>"/>
<br />
Phone Number :
<!-- name of this text field is "phone_num" -->
<input name="phone_num" type="text" id="phone_num" value="<? echo $row['phone_num']; ?>"/>
</p>
Extension :
<!-- name of this text field is "ext" -->
<input name="ext" type="text" id="ext" value="<? echo $row['ext']; ?>"/>
<br />
Title :
<!-- name of this text field is "title" -->
<input name="title" type="text" id="title" value="<? echo $row['title']; ?>"/>
<br />
Department :
<!-- name of this text field is "dept" -->
<input name="dept" type="text" id="dept" value="<? echo $row['dept']; ?>"/>
<br />
Fax Number :
<!-- name of this text field is "fax" -->
<input name="fax" type="text" id="fax" value="<? echo $row['fax']; ?>"/>
<br />
<p>
<input type="submit" name="Submit" value="Submit" />
</p>
</form>
</body>
</html>So now when i use this form does
$id=$_POST['id']; $fname=$_POST['fname']; $lname=$_POST['lname'];
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