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Ignoring First Line of File I/O

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Join Date: Jun 2009

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Ignoring First Line of File I/O

Oct 19th, 2009

Hi.. How do I skip the first line of a text file. I am not using getline() so I think I cannot use ignore() function. Is there any other way to ignore first line ?

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
 
.................
FILE *in;
         char line[1000];
         char *token;
         in = fopen(argv[1],"rt+");
         if( in == NULL) exit(1);
 int i=0; 
 while(! feof(in)) {
 
         //in.ignore(1000, '\n');
//         std::in.ignore ( 1000, '\n' );               
         fgets(line, 1000, in);
.................................
         
.................
FILE *in;
         char line[1000];
         char *token;
         in = fopen(argv[1],"rt+");
         if( in == NULL) exit(1);
 int i=0; 
 while(! feof(in)) {
         
         //in.ignore(1000, '\n');
//         std::in.ignore ( 1000, '\n' );               
         fgets(line, 1000, in);
.................................

Thanks

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Oct 19th, 2009

You can't just simply ignore it. You have to read it and then don't use it for anything.

Don't PM me with questions -- you might get a nasty PM in response. If you have a question then post it in one of the forums.

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amrith92

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Oct 19th, 2009

You could try this:

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
    FILE *in;
    char line[1000];
    char *token;
    in = fopen(argv[1],"rt+");
    if ( in == NULL) exit(1);
    int i=0;
    // Read the first line... move the file pointer to
    // point to the end of the first line. Note that the
    // definition for end-of-line is the '\n' character.
    fgets(line, 1000, in);
    while (! feof(in))
    {
 
        // in.ignore(1000, '\n');
        // std::in.ignore ( 1000, '\n' );
        fgets(line, 1000, in);
        cerr << line << endl;
    }
    FILE *in;
    char line[1000];
    char *token;
    in = fopen(argv[1],"rt+");
    if ( in == NULL) exit(1);
    int i=0;
    // Read the first line... move the file pointer to
    // point to the end of the first line. Note that the
    // definition for end-of-line is the '\n' character.
    fgets(line, 1000, in);
    while (! feof(in))
    {

        // in.ignore(1000, '\n');
        // std::in.ignore ( 1000, '\n' );
        fgets(line, 1000, in);
        cerr << line << endl;
    }

Hope this helped!

Edit: I mean the same thing as what Ancient Dragon said in his post... He answered as I was typing this...

Last edited by amrith92; Oct 19th, 2009 at 3:06 pm.

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Dave Sinkula Dave Sinkula is offline

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long time no c

Oct 19th, 2009

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Originally Posted by amrith92

You could try this:
Help with Code Tags

(Toggle Plain Text)
    fgets(line, 1000, in);
    while (! feof(in))
    {
        // ...
    }
fgets(line, 1000, in); while (! feof(in)) { // ... }

Why it's bad to use feof() to control a loop

[edit]I think the "rt+" mode is a nonstandard extension meaning "r+" .

[edit]And it might be preferable to do

Help with Code Tags

(Toggle Plain Text)

fgets(line, sizeof line, in);

instead of

Help with Code Tags

(Toggle Plain Text)

fgets(line, 1000, in);

(Preferred by me at least.

)

Last edited by Dave Sinkula; Oct 19th, 2009 at 3:43 pm.

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