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buffer cout output and modify cout output order

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Join Date: Oct 2009

Posts: 21

Reputation: raigs is an unknown quantity at this point

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raigs

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Newbie Poster

buffer cout output and modify cout output order

34 Days Ago

N00B. Can I buffer cout, cout something and then cout the buffer? I've been googleing but did not find anything of this sort.

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
#include <iostream>
 
using namespace std;
 
int main (void)
{
	cout << "cout output until this point";
 
	string BUFFER; // I need to buffer the cout output until now.
 
	cout << "Content-length: " + BUFFER.length(); // cout this first.
 
	cout << BUFFER; // cout the BUFFER after the: Content-length.
 
	cout.flush(); // Is this necessary?
 
	return 0;
}
#include <iostream>

using namespace std;

int main (void)
{
	cout << "cout output until this point";

	string BUFFER; // I need to buffer the cout output until now.

	cout << "Content-length: " + BUFFER.length(); // cout this first.

	cout << BUFFER; // cout the BUFFER after the: Content-length.

	cout.flush(); // Is this necessary?

	return 0;
}

•

Join Date: Jul 2005

Posts: 1,676

Reputation: Lerner is a name known to all

Solved Threads: 262

Lerner

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Posting Virtuoso

34 Days Ago

"Content-length: "
That is a string and this:
BUFFER.length()
equates to an int. So when you use the + operator between the two are you trying to concatenate an int onto the string or are you trying to add an int to a string or are what are you trying to do? You could output both like this:

cout << "Content-length: ";
cout << BUFFER.length();

but everything between the << and ; operators in this line:

cout << "Content-length: " + BUFFER.length();

is considered one object so it has to be compatible one way or the other.

Klatu Barada Nikto

•

Join Date: Oct 2009

Posts: 21

Reputation: raigs is an unknown quantity at this point

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raigs

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Newbie Poster

34 Days Ago

•

Originally Posted by Lerner

"Content-length: "
That is a string and this:
BUFFER.length()
equates to an int.

Yes, I made a mistake by concatenating a string and an integer when I drew up that example.

But how can I buffer cout and modify the order they are output?

Last edited by raigs; 34 Days Ago at 5:54 pm.

•

Join Date: Jul 2005

Posts: 1,676

Reputation: Lerner is a name known to all

Solved Threads: 262

Lerner

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Posting Virtuoso

34 Days Ago

Try another example so we can understand better what you are trying to do.

This:
cout << 4 + 7;
works fine as does this:
string word1 = "hello";
string word2 = " world";
cout << word1 + word2;

but I'm not sure what you are thinking about.

Klatu Barada Nikto

•

Join Date: Oct 2009

Posts: 21

Reputation: raigs is an unknown quantity at this point

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raigs

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Newbie Poster

34 Days Ago

Last edited by raigs; 34 Days Ago at 7:08 pm. Reason: double post

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Join Date: Oct 2009

Posts: 21

Reputation: raigs is an unknown quantity at this point

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raigs

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Newbie Poster

34 Days Ago

•

Originally Posted by Lerner

Try another example so we can understand better what you are trying to do.

1. How can I store all the output into a buffer?
2. Then, I have to get the size of that buffer and cout a string stating that buffer's size. How can I achieve this?
3. Then, cout that buffer's content.

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
#include <iostream>
 
using namespace std;
 
int main (void)
{
	cout << "cout output until this point";
 
	string BUFFER; // I need to buffer the cout output until now.
 
	cout << "Content-length: " << BUFFER.length(); // Then, cout the size of the buffer.
 
	cout << BUFFER; // Then, cout that buffer's content.
 
	return 0;
}
#include <iostream>

using namespace std;

int main (void)
{
	cout << "cout output until this point";

	string BUFFER; // I need to buffer the cout output until now.

	cout << "Content-length: " << BUFFER.length(); // Then, cout the size of the buffer.

	cout << BUFFER; // Then, cout that buffer's content.

	return 0;
}