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Printing first letter of string

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Join Date: Oct 2009

Posts: 23

Reputation: th3learner is an unknown quantity at this point

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th3learner th3learner is offline

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Printing first letter of string

Oct 23rd, 2009

 Help with Code Tags 
 c Syntax (Toggle Plain Text) 
#include<iostream.h>
#include<conio.h>
#include<stdio.h>
#include<string.h>
void main()
{
char s[100],z[10];
clrscr();
cout<<"Enter your name:";
gets(s);
cout<<strupr(s[0]);
cout<<".";
getch();
}
#include<iostream.h>
#include<conio.h>
#include<stdio.h>
#include<string.h>
void main()
{
char s[100],z[10];
clrscr();
cout<<"Enter your name:";
gets(s);
cout<<strupr(s[0]);
cout<<".";
getch();
}

what I am looking for is that when user input deniweb,then it should output D
please help

Thanks

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Join Date: Oct 2009

Posts: 45

Reputation: StaticX is an unknown quantity at this point

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StaticX

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Oct 23rd, 2009

If its a c string you could just print out the first element in the array

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
cout << your_array[0]; // prints out first element of array
cout << your_array[0]; // prints out first element of array

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Join Date: Oct 2009

Posts: 23

Reputation: th3learner is an unknown quantity at this point

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th3learner th3learner is offline

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Oct 23rd, 2009

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Originally Posted by StaticX

If its a c string you could just print out the first element in the array
Help with Code Tags

C++ Syntax (Toggle Plain Text)
cout << your_array[0]; // prints out first element of array
cout << your_array[0]; // prints out first element of array

yea i know...but i want first letter should be capital

Thanks

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Join Date: Oct 2009

Posts: 45

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StaticX

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-1

Oct 23rd, 2009

Oh,well you could write a series of if/else if statements like

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
if(my_array[0]=='a' || 'A')
             cout << "A";
            else if(my_array[0]=='b' || 'B')
             cout << "B";
if(my_array[0]=='a' || 'A')
             cout << "A";
            else if(my_array[0]=='b' || 'B')
             cout << "B";

But that would be extremely long winded

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mikiurban

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Oct 23rd, 2009

Does this work?

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
cout<<strupr(s[0]).substring(0,1);
cout<<strupr(s[0]).substring(0,1);

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Join Date: Oct 2009

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th3learner th3learner is offline

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Oct 24th, 2009

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Originally Posted by StaticX

Oh,well you could write a series of if/else if statements like
Help with Code Tags

C++ Syntax (Toggle Plain Text)
if(my_array[0]=='a' || 'A')
             cout << "A";
            else if(my_array[0]=='b' || 'B')
             cout << "B";
if(my_array[0]=='a' || 'A') cout << "A"; else if(my_array[0]=='b' || 'B') cout << "B";
But that would be extremely long winded

Tried , but not works

Input------------>daniweb
Output---------->Ddaniweb

Thanks

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Sky Diploma Sky Diploma is offline

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Oct 24th, 2009

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
cout<<strupr(s[0]);
cout<<strupr(s[0]);

This Does Not Work . Because strupr() takes a char* as an argument. So the argument should be a sting having a null character ie: '\0' at the end. But you give a character as its argument. This is the error.

To solve this problem, You can do two things.
First, You can use the function toupper()
But you will need an additional header file #include <ctype.h> or if you have a modern compiler #include <cctype>
Or else if you wish to use strupr() itself, heres a little snippet..

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
char temp[2];
temp[0]=s[0];
temp[1]='\0';
cout<<strupr(temp);
char temp[2];
temp[0]=s[0];
temp[1]='\0';
cout<<strupr(temp);