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this regular expression

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Join Date: Feb 2008

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johndoe444 johndoe444 is offline

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this regular expression

30 Days Ago

Why is this regular expression (pat) not working? According to documentation, scan takes both string and regexp.

 Help with Code Tags 
 Ruby Syntax (Toggle Plain Text) 
irb(main):001:0> pat = '\d+ (\w+) \(\d+\)'
=> "\\d+ (\\w+) \\(\\d+\\)"
irb(main):002:0> string = 'dfasdf 1 up (2009) sdfasdf 2 walle (2008) adfasdf'
=> "dfasdf 1 up (2009) sdfasdf 2 walle (2008) adfasdf"
irb(main):003:0> string.scan(pat)
=> []
irb(main):001:0> pat = '\d+ (\w+) \(\d+\)'
=> "\\d+ (\\w+) \\(\\d+\\)"
irb(main):002:0> string = 'dfasdf 1 up (2009) sdfasdf 2 walle (2008) adfasdf'
=> "dfasdf 1 up (2009) sdfasdf 2 walle (2008) adfasdf"
irb(main):003:0> string.scan(pat)
=> []

Thanks.

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30 Days Ago

 Help with Code Tags 
 Ruby Syntax (Toggle Plain Text) 
 
pat = '(\d+)'
string = 'dfasdf 1 up (2009) sdfasdf 2 walle (2008) adfasdf'
p string.scan(/#{pat}/)
=>[["1"], ["2009"], ["2"], ["2008"]]
pat = '(\d+)'
string = 'dfasdf 1 up (2009) sdfasdf 2 walle (2008) adfasdf'
p string.scan(/#{pat}/)
=>[["1"], ["2009"], ["2"], ["2008"]]

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Join Date: Feb 2008

Posts: 17

Reputation: johndoe444 is an unknown quantity at this point

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johndoe444 johndoe444 is offline

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30 Days Ago

nice work.

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Originally Posted by xml_looser

Help with Code Tags

Ruby Syntax (Toggle Plain Text)
 
pat = '(\d+)'
string = 'dfasdf 1 up (2009) sdfasdf 2 walle (2008) adfasdf'
p string.scan(/#{pat}/)
=>[["1"], ["2009"], ["2"], ["2008"]]
pat = '(\d+)' string = 'dfasdf 1 up (2009) sdfasdf 2 walle (2008) adfasdf' p string.scan(/#{pat}/) =>[["1"], ["2009"], ["2"], ["2008"]]

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