C program to remove duplicates

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C program to remove duplicates

 
0
  #1
Oct 30th, 2009
Hi, this C program is to remove duplicates. HOwever it doesnt always print out a result and when it does it screws it up sometimes.
C Syntax (Toggle Plain Text) 
  1. # include <stdio.h>
  2. # include "simpio.h"
  3. # include "genlib.h"
  4.  
  5. main()
  6. {
  7.       int a,b,c,d,e,f,g,h,i,j,k,l,m,n,o,p,q,r,s,t,u,v,w,x,y,z,word;
  8.  
  9.       word=getchar();
  10.       a='a';
  11.       b='b';
  12.       c='c';
  13.       d='d';
  14.       e='e';
  15.       f='f';
  16.       g='g';
  17.       h='h';
  18.       i='i';
  19.       j='j';
  20.       k='k';
  21.       l='l';
  22.       m='m';
  23.       n='n';
  24.       o='o';
  25.       p='p';
  26.       q='q';
  27.       r='r';
  28.       s='s';
  29.       t='t';
  30.       u='u';
  31.       v='v';
  32.       w='w';
  33.       x='x';
  34.       y='y';
  35.       z='z';
  36.       while((word=getchar())!=EOF)
  37.       {
  38.       if(word==a)
  39.       {
  40.       printf("a");
  41.       a=1234;
  42.       }
  43. else
  44.       if(word==b)
  45.       {
  46.       printf("b");
  47.       b=1234;
  48.       }
  49. else
  50.       if(word==c)
  51.       {
  52.       printf("c");
  53.       c=1234;
  54.       }
  55. else
  56.       if(word==d)
  57.       {
  58.       printf("d");
  59.       d=1234;
  60.       }
  61. else
  62.       if(word==e)
  63.       {
  64.       printf("e");
  65.       e=1234;
  66.       }
  67. else
  68.       if(word==f)
  69.       {
  70.       printf("f");
  71.       f=1234;
  72.       }
  73. else
  74.       if(word==g)
  75.       {
  76.       printf("g");
  77.       g=1234;
  78.       }
  79. else
  80.       if(word==h)
  81.       {
  82.       printf("h");
  83.       h=1234;
  84.       }
  85. else
  86.       if(word==i)
  87.       {
  88.       printf("i");
  89.       i=1234;
  90.       }
  91. else
  92.       if(word==j)
  93.       {
  94.       printf("j");
  95.       j=1234;
  96.       }
  97. else
  98.       if(word==k)
  99.       {
  100.       printf("k");
  101.       k=1234;
  102.       }
  103. else
  104.       if(word==l)
  105.       {
  106.       printf("l");
  107.       l=1234;
  108.       }
  109. else
  110.       if(word==m)
  111.       {
  112.       printf("m");
  113.       m=1234;
  114.       }
  115. else
  116.       if(word==n)
  117.       {
  118.       printf("n");
  119.       n=1234;
  120.       }
  121. else
  122.       if(word==o)
  123.       {
  124.       printf("o");
  125.       o=1234;
  126.       }
  127. else
  128.       if(word==p)
  129.       {
  130.       printf("p");
  131.       p=1234;
  132.       }
  133. else
  134.       if(word==q)
  135.       {
  136.       printf("q");
  137.       q=1234;
  138.       }
  139. else
  140.       if(word==r)
  141.       {
  142.       printf("r");
  143.       r=1234;
  144.       }
  145. else
  146.       if(word==s)
  147.       {
  148.       printf("s");
  149.       s=1234;
  150.       }
  151. else
  152.       if(word==t)
  153.       {
  154.       printf("t");
  155.       t=1234;
  156.       }
  157. else
  158.       if(word==u)
  159.       {
  160.       printf("u");
  161.       u=1234;
  162.       }
  163. else
  164.       if(word==v)
  165.       {
  166.       printf("v");
  167.       v=1234;
  168.       }
  169. else
  170.       if(word==w)
  171.       {
  172.       printf("w");
  173.       w=1234;
  174.       }
  175. else
  176.       if(word==x)
  177.       {
  178.       printf("x");
  179.       x=1234;
  180.       }
  181. else
  182.       if(word==y)
  183.       {
  184.       printf("y");
  185.       y=1234;
  186.       }
  187. else
  188.       if(word==z)
  189.       {
  190.       printf("z");
  191.       z=1234;
  192.       }
  193.       }
  194.       getchar();
  195. }
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  #2
Oct 31st, 2009
Insert at line 123 ...

C Syntax (Toggle Plain Text) 
  1. else
  2.        {
  3.         printf("\nduplicate or unknown character\n");
  4.        }

and see what you get.
Last edited by SVR; Oct 31st, 2009 at 1:20 am.
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dkalita dkalita is offline Offline
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0
  #3
Nov 2nd, 2009
Thank god there are only 26 alphabets.
If there were 100 u would need to write 100 if statements.

May be u can take some other approach for your problem such as:
write a function like
C Syntax (Toggle Plain Text) 
  1. void removeDuplicate(char *str);
It doesn't necessary that a user wil input a-z. There are many printable characters available.
Implement the above method. If u wanted to do it in C++ u could have used a map of flags such as
C Syntax (Toggle Plain Text) 
  1. map<char, bool> charMap;
When u get a new char in the input string just make an entry as
C Syntax (Toggle Plain Text) 
  1. charMap[myChar] = true; /*that says u have encountered that char*/

If u want to continue with C only u can still do it using an array like
C Syntax (Toggle Plain Text) 
  1. #define MAX_CHAR 100 //whatever the total no. of characters are available
  2. int charEncountered[MAX_CHAR];
  3. //initialize them to 0 (zero)
  4. //use it as
  5. if(charEncountered[myChar]==0)
  6. {
  7.    charEncountered[myChar] = 1;
  8.    //put it in the new buffer
  9. }
  10. else
  11. {
  12.   //duplicate
  13.   //ignore it
  14. }
Last edited by dkalita; Nov 2nd, 2009 at 5:46 am.
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