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Adding digits of a number together

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Adding digits of a number together

 
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  #1
23 Days Ago
I'm trying to make a function that adds the digits of a number together and finds the sum of them.
For example, for the number 9211, I want to add 9 + 2 + 1 + 1 and output the sum.
Here's my function, I can't figure out where I am going wrong.
Could someone point out why the result isn't coming out correctly?

C++ Syntax (Toggle Plain Text) 
  1. #include <iostream>
  2. using namespace std;
  3.  
  4. int SumFunction (int x)
  5. {
  6.    int result = 0;
  7.    result = ((x % 10) + ((x / 10) % 10) + ((x / 100) % 10) + ((x / 1000) % 10) + ((x / 10000) % 10));
  8.    return (result);
  9.  
  10. }
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  #2
23 Days Ago
Formula is correct. It must be something wrong with your function. Post your whole code.
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23 Days Ago
EDIT: The program worked fine all along. I was just using incorrect input! Sorry, you can delete this thread.
Last edited by Towely; 23 Days Ago at 12:52 am.
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  #4
23 Days Ago
Runs fine for me using 1235 and 3459 as input. They're sum buddies and are reported as such. What input is not working for you?
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  #5
23 Days Ago
Oh... the problem was with my input! The program worked fine all along!
I'm so dumb. Sorry for the inconvenience.... You guys can delete this thread.
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  #6
23 Days Ago
dude,
try type casting explicity over the division and mod operation.
The formulae seems to be right. Post ur complete code.









<<BE uniQue
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23 Days Ago
>> result = ((x % 10) + ((x / 10) % 10) + ((x / 100) % 10) + ((x / 1000) % 10) + ((x / 10000) % 10));

You know your formula won't handle number above 99999, try
doing this with for loops or recursions. 
I give up! 
1) What word becomes shorter if you add a letter to it? [ Solved by : niek_e ]
2) What does this sequence  equal to :  (.5u - .5a)(.5u-.5b)(.5u-.5c) ...
3) What is the 123456789 prime numer?
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  #8
23 Days Ago
To make the program obust you need to use looping concept .
This will provide user the freedom of entering any number
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  #9
23 Days Ago
int x=5674876;
int sum=0;
do
{
sum += (x%10);
x /= 10;
}while(x>0);

cout<<"Sum="<<sum;
Last edited by kri_prasad2000; 23 Days Ago at 9:37 am.
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