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String splitting to array...

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Join Date: Oct 2009

Posts: 10

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skiplatte

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String splitting to array...

33 Days Ago

I'm trying to split an input string into an array of substrings and currently trying something like this...

 Help with Code Tags 
 Java Syntax (Toggle Plain Text) 
public static void tryp(String inputString){	
		int index = 0;
 
		String[] rArray = new String[1000];
		String[] kArray = new String[1000];
 
		int startPos = 0;
		int x;
		int newRPos = 0;
		int newKPos = 0;
		String protString;
 
		while (newRPos != -1){
 
		for (x = 0; x < inputString.length(); x++){
 
		int ind = 0;
 
	newRPos = inputString.indexOf('R');
 
String nextRPep = inputString.substring(startPos, (newRPos+1));
protString = inputString.substring(newRPos+1, inputString.length());
		rArray[ind] = nextRPep;
		ind++;
		startPos = newRPos+1;
		newRPos = protString.indexOf('R');
		rArray[ind+1] = protString;
	        }
 
		for (index = 0; index < rArray.length; index++){
 
		newKPos = inputString.indexOf('K');	
 
		while (newKPos != -1){
 
		for (x = 0; x < rArray.length; x++){
 
	        int ind = 0;
 
		String rPep = rArray[x];
 
                String nextPep = rPep.substring(startPos, (newKPos+1));
		protString = rPep.substring(newKPos+1, rPep.length());
		kArray[ind] = nextPep;
		ind++;
		startPos = newKPos+1;
		newKPos = protString.indexOf('K');
		kArray[ind+1] = protString;
	}
	}
	}
}
public static void tryp(String inputString){	
		int index = 0;
		
		String[] rArray = new String[1000];
		String[] kArray = new String[1000];
			
		int startPos = 0;
		int x;
		int newRPos = 0;
		int newKPos = 0;
		String protString;
		
		while (newRPos != -1){
			
		for (x = 0; x < inputString.length(); x++){
				
		int ind = 0;
				
	newRPos = inputString.indexOf('R');
				
String nextRPep = inputString.substring(startPos, (newRPos+1));
protString = inputString.substring(newRPos+1, inputString.length());
		rArray[ind] = nextRPep;
		ind++;
		startPos = newRPos+1;
		newRPos = protString.indexOf('R');
		rArray[ind+1] = protString;
	        }
			
		for (index = 0; index < rArray.length; index++){
			
		newKPos = inputString.indexOf('K');	
			
		while (newKPos != -1){
					
		for (x = 0; x < rArray.length; x++){
				
	        int ind = 0;
				
		String rPep = rArray[x];
		
                String nextPep = rPep.substring(startPos, (newKPos+1));
		protString = rPep.substring(newKPos+1, rPep.length());
		kArray[ind] = nextPep;
		ind++;
		startPos = newKPos+1;
		newKPos = protString.indexOf('K');
		kArray[ind+1] = protString;
	}
	}
	}
}

This compiles but doesn't do what I want....?

Any help much appreciated as I can't think what else I can try (have tried lots that didn't help!)

Thanks

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Join Date: Sep 2008

Posts: 1,598

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BestJewSinceJC BestJewSinceJC is offline

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32 Days Ago

It'd be extremely helpful if you mentioned how you want to split the Strings into substrings (e.g., do you want them to be split around spaces? Around a particular letter? Or what?)

If you read the String class documentation you'll see a method called split() that takes a regular expression as an argument; the method splits the String around matches of the regular expression. So if you were to create a regular expression that matched against the letter "K", then passed that into myString.split(regexForK), then that method call would return a String[], which is exactly what you want.

Out.

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Join Date: Oct 2009

Posts: 10

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skiplatte

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32 Days Ago

I want to split the strings after R and K, retaining those characters. I read about split but it said you can't retain the delimitters when using .split. I tried a tokenizer method which worked quite well, but now have to work out a method using arrays which as you can see is proving v difficult.

Thanks for replying.

•

Originally Posted by BestJewSinceJC

It'd be extremely helpful if you mentioned how you want to split the Strings into substrings (e.g., do you want them to be split around spaces? Around a particular letter? Or what?)

If you read the String class documentation you'll see a method called split() that takes a regular expression as an argument; the method splits the String around matches of the regular expression. So if you were to create a regular expression that matched against the letter "K", then passed that into myString.split(regexForK), then that method call would return a String[], which is exactly what you want.

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Join Date: Sep 2008

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BestJewSinceJC BestJewSinceJC is offline

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Posting Virtuoso

32 Days Ago

If you want a less elegant solution, then simply call String.split() two times on your String. The first time split on R, and the next time split() on K. You already know where your R and K are because they are at the index of the original string where the array was split around. So if you wanted to print out a list of where R was, do something like

 Help with Code Tags 
 Java Syntax (Toggle Plain Text) 
String[] wheresR = myString.split(splitOnR);
int index = 0;
for (String str: wheresR){
index+=str.length();
System.out.println(index);
}
String[] wheresR = myString.split(splitOnR);
int index = 0;
for (String str: wheresR){
index+=str.length();
System.out.println(index);
}

Then I suppose you could have the letter at the beginning or at the end of the String and you wouldn't be sure, but you can check for that as well by using charAt.

Out.

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Join Date: Oct 2009

Posts: 10

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skiplatte

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31 Days Ago

 Help with Code Tags 
 Java Syntax (Toggle Plain Text) 
String[] wheresR = myString.split(splitOnR);
int index = 0;
for (String str: wheresR){
index+=str.length();
System.out.println(index);
}
String[] wheresR = myString.split(splitOnR);
int index = 0;
for (String str: wheresR){
index+=str.length();
System.out.println(index);
}

Say myString was AMLARMLAKFGFP .... would this return AMLAR, MLAK, FGFP ? Or would I have to reinsert the R/Ks separately?

Thanks

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Join Date: Sep 2008

Posts: 1,598

Reputation: BestJewSinceJC is a name known to all

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BestJewSinceJC BestJewSinceJC is offline

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Posting Virtuoso

31 Days Ago

Like the docs say, split does not return the character that was split around. My point in my previous post was that you can easily figure out where the characters were anyway by using a little intuition.

Out.

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Join Date: May 2007

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Ezzaral

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Industrious Poster

31 Days Ago

Using the pattern (\w+?[RK]) with the regex Matcher.find() method will capture all of those groups except for the last one, which doesn't end with R or K.

Edit: This pattern \w+?[RK]|\G\w++$ seems to produce the result you wanted.

 Help with Code Tags 
 Java Syntax (Toggle Plain Text) 
Pattern pat = Pattern.compile("\\w+?[RK]|\\G\\w++$");
String input = "AMLARMLAKFGFP";
Matcher matcher = pat.matcher(input);
while (matcher.find()){
    System.out.println(matcher.group());
}
Pattern pat = Pattern.compile("\\w+?[RK]|\\G\\w++$");
String input = "AMLARMLAKFGFP";
Matcher matcher = pat.matcher(input);
while (matcher.find()){
    System.out.println(matcher.group());
}

Last edited by Ezzaral; 31 Days Ago at 5:02 pm.

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Join Date: Oct 2009

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skiplatte

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30 Days Ago

Omg it works! Thank you so much

It also does seem to return the last sequence (FGFP), at least for print out. Can I insert the matcher groups into a string array using something like

[CODE]
String trypArray = new String[1000];
int indx = 0;

while (matcher.find()){
trypArray[indx] = (matcher.group());
indx++
}
[iCODE]

and/or is there a better/simpler way to pass the result of matcher.group() to another method (in my case where the weight of the string is calculated using key/values from a hashmap)?

Many many thanks

•

Originally Posted by Ezzaral

Using the pattern (\w+?[RK]) with the regex Matcher.find() method will capture all of those groups except for the last one, which doesn't end with R or K.

Edit: This pattern \w+?[RK]|\G\w++$ seems to produce the result you wanted.
Help with Code Tags

Java Syntax (Toggle Plain Text)
Pattern pat = Pattern.compile("\\w+?[RK]|\\G\\w++$");
String input = "AMLARMLAKFGFP";
Matcher matcher = pat.matcher(input);
while (matcher.find()){
    System.out.println(matcher.group());
}
Pattern pat = Pattern.compile("\\w+?[RK]|\\G\\w++$"); String input = "AMLARMLAKFGFP"; Matcher matcher = pat.matcher(input); while (matcher.find()){ System.out.println(matcher.group()); }