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while loop in python

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Join Date: Nov 2009

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laxter17

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while loop in python

34 Days Ago

I am totally new to programming and could use some help.

I am trying to write a while loop in python that could execute this equation but in a while loop type function.

the equation is n * (n + 1) / 2

any ideas?

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Join Date: Nov 2009

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ShadyTyrant ShadyTyrant is offline

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34 Days Ago

Could you be more clear on the conditions you want met?

 Help with Code Tags 
 Python Syntax (Toggle Plain Text) 
while True:
    answer = n * (n + 1) / 2
    print answer
while True:
    answer = n * (n + 1) / 2
    print answer

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Join Date: Nov 2009

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laxter17

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34 Days Ago

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Originally Posted by ShadyTyrant

Could you be more clear on the conditions you want met?
Help with Code Tags

Python Syntax (Toggle Plain Text)
while True:
    answer = n * (n + 1) / 2
    print answer
while True: answer = n * (n + 1) / 2 print answer

I have written 2 functions already, they are:

def sum1(n):
result = n * (n + 1) / 2
print result

def sum2(n):
sum = 0
for x in range(1,n+1):
sum = x + sum
print sum

And this what I need to do for the third function:

The third function (call it "sum3") computes and prints the answer using a "while" loop. In some respects the code is similar to the "for" loop of part 2 above. However, unlike a "for" loop, you have to initialize a counting variable, test to see if it is small enough (using the while loop) and if so, execute the loop body. In the body you must increment the counting variable. This function is about 6 lines long.

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Join Date: Jul 2009

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Reputation: masterofpuppets is an unknown quantity at this point

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masterofpuppets masterofpuppets is offline

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34 Days Ago

well I think you answered the question

you know how to create the while loop

here's a hint:

 Help with Code Tags 
 Python Syntax (Toggle Plain Text) 
>>> count = 0
>>> while count < 5:
	print count
	count = count + 1
 
 
0
1
2
3
4
>>>
>>> count = 0
>>> while count < 5:
	print count
	count = count + 1

	
0
1
2
3
4
>>>

Hope this helps

My site ->> http://8masterofpuppets8.webs.com/
"My belief is stronger than your doubt."

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Join Date: Nov 2009

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ShadyTyrant ShadyTyrant is offline

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34 Days Ago

Im not really sure what your computing or what you need in the body but the while loop and the increment should be what your looking for.

 Help with Code Tags 
 Python Syntax (Toggle Plain Text) 
def sum3(n):
    i = 0
    while i <= n+1:
        sum = n * (n + 1) / 2  
        print sum
        i += 1
        # same as i = i + 1
def sum3(n):
    i = 0
    while i <= n+1:
        sum = n * (n + 1) / 2  
        print sum
        i += 1
        # same as i = i + 1

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jlm699

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Knows where his Towel is

34 Days Ago

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Originally Posted by laxter17

And this what I need to do for the third function:

The third function (call it "sum3") computes and prints the answer using a "while" loop. In some respects the code is similar to the "for" loop of part 2 above. However, unlike a "for" loop, you have to initialize a counting variable, test to see if it is small enough (using the while loop) and if so, execute the loop body. In the body you must increment the counting variable. This function is about 6 lines long.

We can't really do your homework for you, but the basics of a while loop are like this.

 Help with Code Tags 
 Python Syntax (Toggle Plain Text) 
some_flag = initial_state
while some_flag (does not meet) my_condition:
    perform action
    update some_flag
some_flag = initial_state
while some_flag (does not meet) my_condition:
    perform action
    update some_flag

So initially some_flag does not meet the desired condition. The loop continually updates the value of some_flag , and when it finally meets the condition that you specify, the loop automatically breaks.

You could alternately simply do a while True: loop (super loop or infinite loop), and then compare the flag to a condition using an if statement. If the flag meets the condition, use break to break out of the super loop.

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