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Hwk: how do I make a 2d array of pointers point to another array

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Join Date: Nov 2009

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Tamaki

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Hwk: how do I make a 2d array of pointers point to another array

20 Days Ago

Hi, I'm new here and I just need a little help with pointers and 2D arrays. I'm kind of new to programming so this might be redundant. I'm trying to make a 2D array of pointers (already have done) that points to another 2D array of double values... I have the code:

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for (i = 0; i < n; i++)
	for (j = 0; j < n; j++)
		ptrA[i][j] = a[j][i];
for (i = 0; i < n; i++)
	for (j = 0; j < n; j++)
		ptrA[i][j] = a[j][i];

**its transposed for a reason**

However when I do calculations on array ptrA, it doesnt change the values in array a...

ptrA and a are declared by

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double a[n][n];
double temp;
for (i = 0; i < n; i++){			//intializing [A] to inputs
	for (j = 0; j < n; j++){ 
		scanf("%lf", &temp);
		a[i][j] = temp;
	}
}
 
double **ptrA = malloc(n*sizeof(*ptrA));
if (ptrA != NULL){
	for (i = 0; i < n; i++)
		ptrA[i] = malloc(n*sizeof(*ptrA[i]));
} else return 1;
double a[n][n];
double temp;
for (i = 0; i < n; i++){			//intializing [A] to inputs
	for (j = 0; j < n; j++){ 
		scanf("%lf", &temp);
		a[i][j] = temp;
	}
}

double **ptrA = malloc(n*sizeof(*ptrA));
if (ptrA != NULL){
	for (i = 0; i < n; i++)
		ptrA[i] = malloc(n*sizeof(*ptrA[i]));
} else return 1;

Last edited by Tamaki; 20 Days Ago at 2:20 pm.

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Ancient Dragon Ancient Dragon is offline

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19 Days Ago

variable ptrA needs to have three stars

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#define maxrows  2
#define maxcols 5
 
 
int main()
{
	double a[maxrows][maxcols];
	double ***ptrA = malloc(maxrows * sizeof(double*));
	int i,j;
 
	for(i = 0; i < maxrows; i++)
	{
		ptrA[i] = malloc(maxcols * sizeof(double*));
		for(j = 0; j < maxcols; j++)
		{
			ptrA[i][j] = &a[i][j];
		}
	}
}
#define maxrows  2
#define maxcols 5


int main()
{
	double a[maxrows][maxcols];
	double ***ptrA = malloc(maxrows * sizeof(double*));
	int i,j;

	for(i = 0; i < maxrows; i++)
	{
		ptrA[i] = malloc(maxcols * sizeof(double*));
		for(j = 0; j < maxcols; j++)
		{
			ptrA[i][j] = &a[i][j];
		}
	}
}