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Dr. MyName, or how I learned to stop worrying and love using strings in functions

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Join Date: Oct 2009

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calypso&noname calypso&noname is offline

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Dr. MyName, or how I learned to stop worrying and love using strings in functions

Nov 2nd, 2009

Hi friends;

I've run into a problem trying to complete the below assignment:

Write a function called myName which returns (does not cout) your full name (e.g., "Bob Smith"). Write main to call the function and display the name on the screen. NOTE: Your name should not appear anywhere other than in the function myName.

The problem, as I understand it, is that the string MyName cannot be converted into an integer, and the function must use int to define itself.

I'm between a rock and a hard place, and I keep running into error code C2440: 'return' : cannot convert from 'std::string' to 'int'

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
#include <iostream>
#include <string>
 
using namespace std;
 
int MyName()
{
	string MyName = "TK 421";
	return MyName;
}
int main ()
{
	MyName();
}
#include <iostream>
#include <string>

using namespace std;

int MyName()
{
	string MyName = "TK 421";
	return MyName;
}
int main ()
{
	MyName();
}

Also I used my skills in the internets to try to solve the problem, but the best I found was a bit of code that used a char function as a pointer to the string. Or something like that, but I didn't understand it and I'm not sure I'm allowed to do it for this problem. If it is the only way, could someone explain how it works please?

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Join Date: Sep 2009

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jonsca

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Nov 2nd, 2009

Why can't myName() return a string instead of an int? Also, the restriction on cout seems to be for your function body only.

Great post title, BTW.

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Join Date: Oct 2009

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calypso&noname calypso&noname is offline

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Nov 2nd, 2009

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Originally Posted by jonsca

Why can't myName() return a string instead of an int? Also, the restriction on cout seems to be for your function body only.

Great post title, BTW.

Hey Jonsca; thanks, glad you liked it.

I'm not sure why exactly it can't return the string. My guess is that the program tries to convert the string to an integer, since it's in an integer function. However, this doesn't work, since 1) the string is characters, not numbers, and 2) the string has a space in it.

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Join Date: Sep 2009

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jonsca

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Posting Pro in Training

Nov 2nd, 2009

But why does your function return an int if you want it to return a string? Was your assignment given that way? Just saying it doesn't make much sense. If you need to return a string, just change the return type of the function string myName() { etc. }

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Join Date: Jun 2009

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necrolin

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Nov 2nd, 2009

You have one of a few choices:

1. Convert your function from returning an int to returning a string
2. Convert MyName to an integer.... maybe something like MyID
3. Convert your function to return a void* and then cast it to a string...

Of these choices, option 1 is the best. You cannot return a string when you are specifically telling the program that it must return an int.

My ideas in code:

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
#include <iostream>
#include <string>
 
using namespace std;
 
string MyName()
{
    return "Hubba Bubba";
}
 
int MyID()
{
    return 1234;
}
 
void* MyName2()
{
    static string name = "Hubba Bubba Jr.";
    void* temp = &name;
    return temp;
}
 
int main()
{
    string name1 = MyName();
    void* name2 = MyName2();
    int ID = MyID();
 
    cout << name1 << endl;
    cout << *(string*)name2 << endl;
    cout << ID << endl;
 
    return 0;
}
#include <iostream>
#include <string>

using namespace std;

string MyName()
{
    return "Hubba Bubba";
}

int MyID()
{
    return 1234;
}

void* MyName2()
{
    static string name = "Hubba Bubba Jr.";
    void* temp = &name;
    return temp;
}

int main()
{
    string name1 = MyName();
    void* name2 = MyName2();
    int ID = MyID();

    cout << name1 << endl;
    cout << *(string*)name2 << endl;
    cout << ID << endl;

    return 0;
}

Last edited by necrolin; Nov 2nd, 2009 at 10:40 pm.

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34 Days Ago

Thanks a lot Necrolin; I could've sworn I had tried that before without good results, but it worked perfectly. Thanks for giving me multiple options too; it's great to see different ways of doing the same thing.