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Zeroing bits
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Is this the proper way to zero the first 12 bits of an address?
Where addr is any user process memory address..
Note this method works...I just want to know if there is a better way
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Where addr is any user process memory address..
Note this method works...I just want to know if there is a better way
Last edited by gerard4143; 15 Days Ago at 12:05 pm.
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#2 15 Days Ago
I'd just do a bitwise shift left 12 then a bitwise shift right 12
There are 10 types of people in the world, those who get this, those who don't, and those who thought this was binary.
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#3 15 Days Ago
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Originally Posted by kolosick.m188 
I'd just do a bitwise shift left 12 then a bitwise shift right 12
Last edited by gerard4143; 15 Days Ago at 1:54 pm.
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#4 15 Days Ago
Here's what I mean
1010101010101111
First twelve is 101010101010
Shift left twelve gives
1111000000000000
Shift right twelve then gives
0000000000001111
1010101010101111
First twelve is 101010101010
Shift left twelve gives
1111000000000000
Shift right twelve then gives
0000000000001111
There are 10 types of people in the world, those who get this, those who don't, and those who thought this was binary.
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#5 15 Days Ago
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Originally Posted by kolosick.m188
Here's what I mean
1010101010101111
First twelve is 101010101010
Shift left twelve gives
1111000000000000
Shift right twelve then gives
0000000000001111
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#6 15 Days Ago
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Originally Posted by gerard4143
Is this the proper way to zero the first 12 bits of an address?
Where addr is any user process memory address..void *ans = (void*)((unsigned long)addr & ((0UL - 1) ^ 0xfff));
Note this method works...I just want to know if there is a better way
void *ans = (void*)((unsigned long)addr & ~0xfffUL); "One of the methods used by statists to destroy capitalism consists in establishing controls that tie a given industry hand and foot, making it unable to solve its problems, then declaring that freedom has failed and stronger controls are necessary." --Ayn Rand
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