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Reading and editing characters in a string

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Join Date: Oct 2009

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shakunni

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Reading and editing characters in a string

Nov 9th, 2009

I need to edit every character of a string for an assignment; apply a simple Caesar cipher on it. What is the C equivalent of "charAt()"? I remember my prof saying that all strings are terminated with a certain character in C and that you could run a while loop till that character, but I'm not sure how to do it.

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adatapost

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Nov 10th, 2009

C string is an array of characters. You may set or get a character at specific index.

 Help with Code Tags 
 C Syntax (Toggle Plain Text) 
char str[20]="ABC";
str[0]='a'; // replace 'A' with 'a'
char str[20]="ABC";
str[0]='a'; // replace 'A' with 'a'

C String (char array) is terminated with a '\0' (null) character.

 Help with Code Tags 
 C Syntax (Toggle Plain Text) 
 char str[20]="Sample Text";
 int i=0;
 while(str[i]!='\0') {
     /* put your code */
    i++;
 }
 char str[20]="Sample Text";
 int i=0;
 while(str[i]!='\0') {
     /* put your code */
    i++;
 }

Last edited by adatapost; Nov 10th, 2009 at 7:20 am.

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Join Date: Oct 2009

Posts: 28

Reputation: shakunni is an unknown quantity at this point

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shakunni

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Nov 10th, 2009

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Originally Posted by adatapost

C string is an array of characters. You may set or get a character at specific index.
Help with Code Tags

C Syntax (Toggle Plain Text)
char str[20]="ABC";
str[0]='a'; // replace 'A' with 'a'
char str[20]="ABC"; str[0]='a'; // replace 'A' with 'a'
C String (char array) is terminated with a '\0' (null) character.
Help with Code Tags

C Syntax (Toggle Plain Text)
 char str[20]="Sample Text";
 int i=0;
 while(str[i]!='\0') {
     /* put your code */
    i++;
 }
char str[20]="Sample Text"; int i=0; while(str[i]!='\0') { /* put your code */ i++; }