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hi i am new to this forum and my major is computer science...this is the best thing i found on the web yet....i will try to help you out anyway i can.....i need help on this program...thanks
1. create a dynamicarray to hold the first 10 odd intergers. now create the array to triple its size to hold the first 30 odd integers.
1. create a dynamicarray to hold the first 10 odd intergers. now create the array to triple its size to hold the first 30 odd integers.
For arrays read here:-
http://www.cprogramming.com/tutorial/lesson8.html
For modulus operator, read here:-
http://www.cprogramming.com/tutorial/modulus.html
You'll be needing for loops also. So read here:-
http://www.cprogramming.com/tutorial/lesson3.html
I suggest you declare a global variable call SIZE (and equate it to 10).
And use the SIZE in your array like this:-
array [SIZE];
and in your for loop also. Like this:-
for (int i=0; i<SIZE; i++)
{
For the second part of the question, just equate SIZE (your global variable) to 30.
Hope this helps.
http://www.cprogramming.com/tutorial/lesson8.html
For modulus operator, read here:-
http://www.cprogramming.com/tutorial/modulus.html
You'll be needing for loops also. So read here:-
http://www.cprogramming.com/tutorial/lesson3.html
I suggest you declare a global variable call SIZE (and equate it to 10).
And use the SIZE in your array like this:-
array [SIZE];
and in your for loop also. Like this:-
for (int i=0; i<SIZE; i++)
{
:
do your odd number generator here
and equate it into your dynamic array
:}
For the second part of the question, just equate SIZE (your global variable) to 30.
Hope this helps.
ok here we go.....ERRORS...
<< moderator edit: added [code][/code] tags >>
C++ Syntax (Toggle Plain Text)
#include <iostream> using namespace std; int main () { int num_cells=10; int * a; a * new int[num_cells]; for (int i=0; i<num_cells; i++) a(i)=30*1+1; cout<<"a:"; for (i=0; i<num_cells; i++) int=b; b=new int [3*num_cells]; cout<<a(i)<< cout <<endl; for(i=0; i<num_cells; i++) b (i) = a(i); delete [] a; num_cells *=3; a=b; b=nul; cout << "Size of array has tripled\n"; for (i=num_cells; i<num_cells; i++) a(i>=10*i+1); cout<<"a:"; for (i=0; i<num_cells; i++) cout << a [1]<<""; cout<<endl; delete [] a; return 0; }
Arrays are indexed a[i], not a(i). Typo? Did you mean i instead of int? b? nul?
Learn to use whitespace to make your code easier to read.
a * new int[num_cells];a = new int[num_cells]; C++ Syntax (Toggle Plain Text)
int=b;
C++ Syntax (Toggle Plain Text)
b=nul;
Learn to use whitespace to make your code easier to read.
"One of the methods used by statists to destroy capitalism consists in establishing controls that tie a given industry hand and foot, making it unable to solve its problems, then declaring that freedom has failed and stronger controls are necessary." --Ayn Rand
Well, your codes are a little misleading. I don't quite understand what you are doing. Anyway, I'll go step by step with you. First, make sure you have this in mind:- A 10 block array like this [] [] [] [] [] [] [] [] [] []
Here, I can only interpret one thing. The array will be filled with number 31 like this:- [31] [31] [31] [31] [31] [31] [31] [31] [31] [31]
But on screen you'll only see a: as you didn't include the output into your loop
Then, I see that you transfer the array a to array b. Which I do not see the need for this. But please correct me if I'm wrong
If everything works well, you'll only get something like this a [1]a [1]a [1]a [1]a [1]a [1]a [1]a [1]a [1]a [1]
The rest of the problem, I believe Dave had already mention them.
C++ Syntax (Toggle Plain Text)
for (int i=0; i<num_cells; i++) a[i]=30*1+1; cout<<"a:";
But on screen you'll only see a: as you didn't include the output into your loop
Then, I see that you transfer the array a to array b. Which I do not see the need for this. But please correct me if I'm wrong
C++ Syntax (Toggle Plain Text)
for(i=0; i<num_cells; i++) b [i] = a[i];
C++ Syntax (Toggle Plain Text)
for (i=0; i<num_cells; i++) cout << a [1]<<"";
If everything works well, you'll only get something like this a [1]a [1]a [1]a [1]a [1]a [1]a [1]a [1]a [1]a [1]
The rest of the problem, I believe Dave had already mention them.
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