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Join Date: Apr 2005
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Newbie Poster
hi i am new to this forum and my major is computer science...this is the best thing i found on the web yet....i will try to help you out anyway i can.....i need help on this program...thanks
1. create a dynamicarray to hold the first 10 odd intergers. now create the array to triple its size to hold the first 30 odd integers.
1. create a dynamicarray to hold the first 10 odd intergers. now create the array to triple its size to hold the first 30 odd integers.
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Join Date: Apr 2005
Location: Oklahoma
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Junior Poster in Training
So, what have you done so far? Do you not understand the assignment?
Hint: use a for loop, the modulus operator with the number two to find if it is even or odd
Hint: use a for loop, the modulus operator with the number two to find if it is even or odd
Yeah... I'm lazy. Deal with it.
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Join Date: Aug 2004
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Newbie Poster
For arrays read here:-
http://www.cprogramming.com/tutorial/lesson8.html
For modulus operator, read here:-
http://www.cprogramming.com/tutorial/modulus.html
You'll be needing for loops also. So read here:-
http://www.cprogramming.com/tutorial/lesson3.html
I suggest you declare a global variable call SIZE (and equate it to 10).
And use the SIZE in your array like this:-
array [SIZE];
and in your for loop also. Like this:-
for (int i=0; i<SIZE; i++)
{
For the second part of the question, just equate SIZE (your global variable) to 30.
Hope this helps.
http://www.cprogramming.com/tutorial/lesson8.html
For modulus operator, read here:-
http://www.cprogramming.com/tutorial/modulus.html
You'll be needing for loops also. So read here:-
http://www.cprogramming.com/tutorial/lesson3.html
I suggest you declare a global variable call SIZE (and equate it to 10).
And use the SIZE in your array like this:-
array [SIZE];
and in your for loop also. Like this:-
for (int i=0; i<SIZE; i++)
{
:
do your odd number generator here
and equate it into your dynamic array
:}
For the second part of the question, just equate SIZE (your global variable) to 30.
Hope this helps.
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Newbie Poster
ok i will do this...and post here...and if there's any error pls help me out
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Join Date: Apr 2005
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Newbie Poster
ok here we go.....ERRORS...
<< moderator edit: added [code][/code] tags >>
#include <iostream>
using namespace std;
int main ()
{
int num_cells=10;
int * a;
a * new int[num_cells];
for (int i=0; i<num_cells; i++)
a(i)=30*1+1;
cout<<"a:";
for (i=0; i<num_cells; i++)
int=b;
b=new int [3*num_cells];
cout<<a(i)<<
cout <<endl;
for(i=0; i<num_cells; i++)
b (i) = a(i);
delete [] a;
num_cells *=3;
a=b;
b=nul;
cout << "Size of array has tripled\n";
for (i=num_cells; i<num_cells; i++)
a(i>=10*i+1);
cout<<"a:";
for (i=0; i<num_cells; i++)
cout << a [1]<<"";
cout<<endl;
delete [] a;
return 0;
} •
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Join Date: Apr 2004
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Arrays are indexed a[i], not a(i). Typo? Did you mean i instead of int? b? nul?
Learn to use whitespace to make your code easier to read.
a * new int[num_cells];a = new int[num_cells];int=b;
b=nul;
Learn to use whitespace to make your code easier to read.
High Plains Blogger #plains #lounge ## I, for one, welcome our new socialist overlords.
"Capitalism is the unequal distribution of wealth. Socialism is the equal distribution of poverty."
"Capitalism is the unequal distribution of wealth. Socialism is the equal distribution of poverty."
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Join Date: Aug 2004
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Newbie Poster
Well, your codes are a little misleading. I don't quite understand what you are doing. Anyway, I'll go step by step with you. First, make sure you have this in mind:- A 10 block array like this [] [] [] [] [] [] [] [] [] []
Here, I can only interpret one thing. The array will be filled with number 31 like this:- [31] [31] [31] [31] [31] [31] [31] [31] [31] [31]
But on screen you'll only see a: as you didn't include the output into your loop
Then, I see that you transfer the array a to array b. Which I do not see the need for this. But please correct me if I'm wrong
If everything works well, you'll only get something like this a [1]a [1]a [1]a [1]a [1]a [1]a [1]a [1]a [1]a [1]
The rest of the problem, I believe Dave had already mention them.
for (int i=0; i<num_cells; i++) a[i]=30*1+1; cout<<"a:";
But on screen you'll only see a: as you didn't include the output into your loop
Then, I see that you transfer the array a to array b. Which I do not see the need for this. But please correct me if I'm wrong
for(i=0; i<num_cells; i++) b [i] = a[i];
for (i=0; i<num_cells; i++) cout << a [1]<<"";
If everything works well, you'll only get something like this a [1]a [1]a [1]a [1]a [1]a [1]a [1]a [1]a [1]a [1]
The rest of the problem, I believe Dave had already mention them.
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