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Zip files, move files, delete source (help me please)

  #1  
Aug 30th, 2005
Hello this is my first post on these forums.

For a little back ground into this, I recently installed a Linux server with the purpose of recording matches via a program called HLTV.

Now what I want to do is take the individual .dem files compress them one by one then move the compressed files to a different folder and delete the originals

I found a script that seemed to do the job but it doesn’t work and I can’t seem to debug it.

#!/bin/bash
HLDS= /hlds/cstrike/ #Working directory where demos are
REP=/hlds/cstrike/demos/ #copying directory
FORMAT=tar cvf
EXTENSION=tar
#FORMAT=zip #Compression using ZIP
#EXTENSION=zip #Associated extension
cd $HLDS
for files in `ls *.dem` do
     $FORMAT $files.$(date +%s).$EXTENSION $files
     echo "$files.$(date +%s).$EXTENSION compressed"
     mv $files.$(date +%s).$EXTENSION $REP
     echo "$files.$(date +%s).$EXTENSION moved"
     rm $files
     echo "$files deleted"
done;
echo "Demos are available in : $REP"

the source folder is /hlds/cstrike
destination folder is /hlds/cstrike/demos

file type is .dem


Thanks for any help.
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Re: Zip files, move files, delete source (help me please)

  #2  
Sep 12th, 2005
without really looking hard at the code, these variable declarations will not work

this one the space can't be used
HLDS= /hlds/cstrike/
it needs to be
HLDS=/hlds/cstrike

also this will not work
FORMAT=tar cvf
I think you want to do this, you will need to place it in quotes
FORMAT="tar cvf"
In a perfect world exceptions would not be needed.
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Re: Zip files, move files, delete source (help me please)

  #3  
Sep 12th, 2005
Thanks for the help
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Re: Zip files, move files, delete source (help me please)

  #4  
Sep 12th, 2005
your welcome :-)

is it doing what you want it to?
In a perfect world exceptions would not be needed.
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Re: Zip files, move files, delete source (help me please)

  #5  
Sep 12th, 2005
actually I was just about to give it a try

Im hoping so, would save me a bit of work
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