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session_start(): Cannot send session cookie - headers already sent by

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Join Date: Jun 2006

Posts: 10

Reputation: manish812 is an unknown quantity at this point

Solved Threads: 1

manish812

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Newbie Poster

session_start(): Cannot send session cookie - headers already sent by

Jun 21st, 2006

hi
thrr is no one who can help me this is the prog which when i run faces problem of session.

session_start(): Cannot send session cookie - headers already sent

pls plssssssssss help me to solve the problem below is the code

any one this is simple prog but i can't run
if i can't run thn my boss will kick me out of the office.
so pls hlp me.

[php]<?session_start();?>
<?php
include"db_config.php";
$connect = mysql_connect("$db_host", "$db_user", "$db_password");
mysql_select_db("$db_name", $connect) or die(mysql_error());
$f_name= $_POST['fname'];
$l_name= $_POST['lname'];
$pass= $_POST['password'];
$query = "SELECT * from helpagent WHERE first='$f_name' and last='$l_name' and password='$pass' ";
$result = mysql_query($query);
for ($i = 0; $i < mysql_num_rows($result); $i++)
{
$id = mysql_result($result, $i, "agentid");
$fname = mysql_result($result, $i, "first");
$lname = mysql_result($result, $i, "last");
$pas = mysql_result($result, $i, "password");
if (("$f_name" == "$fname") and ("$l_name" == "$lname") and ("$pass" == "$pas"))
{
$_SESSION['sfname'] = $fname;
$_SESSION['slname'] = $lname;
$_SESSION['sid'] = $id;
echo("<script>document.location.href='user_page.php';</script>");
exit;
}//if loop
}//for loop
?>[/php]

Last edited by cscgal; Jun 30th, 2006 at 7:42 pm.

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Join Date: Jul 2004

Posts: 494

Reputation: Puckdropper is an unknown quantity at this point

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Puckdropper Puckdropper is offline

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Re: session_start(): Cannot send session cookie - headers already sent by

Jun 21st, 2006

I suggest you read the other threads you started, as well as the manual. There are also some very good how-tos out there to teach you how to properly do what you want to.

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Join Date: Mar 2005

Posts: 48

Reputation: RamiroS is an unknown quantity at this point

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RamiroS

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Re: session_start(): Cannot send session cookie - headers already sent by

Jun 29th, 2006

Check the manual... if that script is included check that the file that it is actually including it doesn't have any print or echo. session_start() should be at the very beginning of the code.

Also change this:

[php]
<?session_start();?>
<?php
include"db_config.php";
[/php]

to this

[php]
<?php
session_start();
include"db_config.php";
[/php]

There is no need to break the PHP tags there... and use <?php also instead of <? it will make the script work in other servers. Or maybe your server doesn;t support short php tags.

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Join Date: Feb 2006

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BlazingWolf BlazingWolf is offline

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Re: session_start(): Cannot send session cookie - headers already sent by

Jul 1st, 2006

I'm assuming that your including this file into another file, and in that other file you have already echoed something when this file is included.

Otherwise I cannot see what is wrong, as suggested the manual always helps.

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Join Date: Oct 2009

Posts: 1

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berhansoner berhansoner is offline

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-1

Oct 26th, 2009

Be sure that your SafeMode CLOSED. Ask your hosting company t switch it to CLOSED. The problem will be solved

•

Originally Posted by manish812

hi
thrr is no one who can help me this is the prog which when i run faces problem of session.

session_start(): Cannot send session cookie - headers already sent

pls plssssssssss help me to solve the problem below is the code

any one this is simple prog but i can't run
if i can't run thn my boss will kick me out of the office.
so pls hlp me.

[php]<?session_start();?>
<?php
include"db_config.php";
$connect = mysql_connect("$db_host", "$db_user", "$db_password");
mysql_select_db("$db_name", $connect) or die(mysql_error());
$f_name= $_POST['fname'];
$l_name= $_POST['lname'];
$pass= $_POST['password'];
$query = "SELECT * from helpagent WHERE first='$f_name' and last='$l_name' and password='$pass' ";
$result = mysql_query($query);
for ($i = 0; $i < mysql_num_rows($result); $i++)
{
$id = mysql_result($result, $i, "agentid");
$fname = mysql_result($result, $i, "first");
$lname = mysql_result($result, $i, "last");
$pas = mysql_result($result, $i, "password");
if (("$f_name" == "$fname") and ("$l_name" == "$lname") and ("$pass" == "$pas"))
{
$_SESSION['sfname'] = $fname;
$_SESSION['slname'] = $lname;
$_SESSION['sid'] = $id;
echo("<script>document.location.href='user_page.php';</script>");
exit;
}//if loop
}//for loop
?>[/php]

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Join Date: Oct 2009

Posts: 15

Reputation: alagirinetaxis is an unknown quantity at this point

Solved Threads: 3

alagirinetaxis alagirinetaxis is offline

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Oct 27th, 2009

 Help with Code Tags 
 PHP Syntax (Toggle Plain Text) 
<?php session_start();
ob_start();
 
include"db_config.php";
 
$connect = mysql_connect("$db_host", "$db_user", "$db_password");
mysql_select_db("$db_name", $connect) or die(mysql_error());
$f_name= $_POST['fname'];
$l_name= $_POST['lname'];
$pass= $_POST['password'];
$query = "SELECT * from helpagent WHERE first='$f_name' and last='$l_name' and password='$pass' ";
$result = mysql_query($query);
for ($i = 0; $i < mysql_num_rows($result); $i++)
{
$id = mysql_result($result, $i, "agentid");
$fname = mysql_result($result, $i, "first");
$lname = mysql_result($result, $i, "last");
$pas = mysql_result($result, $i, "password");
if (("$f_name" == "$fname") and ("$l_name" == "$lname") and ("$pass" == "$pas"))
{
$_SESSION['sfname'] = $fname;
$_SESSION['slname'] = $lname;
$_SESSION['sid'] = $id;
echo("<script>document.location.href='user_page.php';</script>");
exit;
}//if loop
}//for loop
?>
<?php session_start();
ob_start();

include"db_config.php";

$connect = mysql_connect("$db_host", "$db_user", "$db_password");
mysql_select_db("$db_name", $connect) or die(mysql_error());
$f_name= $_POST['fname'];
$l_name= $_POST['lname'];
$pass= $_POST['password'];
$query = "SELECT * from helpagent WHERE first='$f_name' and last='$l_name' and password='$pass' ";
$result = mysql_query($query);
for ($i = 0; $i < mysql_num_rows($result); $i++)
{
$id = mysql_result($result, $i, "agentid");
$fname = mysql_result($result, $i, "first");
$lname = mysql_result($result, $i, "last");
$pas = mysql_result($result, $i, "password");
if (("$f_name" == "$fname") and ("$l_name" == "$lname") and ("$pass" == "$pas"))
{
$_SESSION['sfname'] = $fname;
$_SESSION['slname'] = $lname;
$_SESSION['sid'] = $id;
echo("<script>document.location.href='user_page.php';</script>");
exit;
}//if loop
}//for loop
?>

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Join Date: Nov 2009

Posts: 1

Reputation: toddor is an unknown quantity at this point

Solved Threads: 0

toddor

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Newbie Poster

16 Days Ago

Sometimes the problem is caused by the Dreamweaver's "Include Unicode Signature (BOM)" property.
To turn it off go to Modify > Page Properties > Title/Encoding in Dreamweaver and uncheck "Include Unicode Signature (BOM)"