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sum of the linked list
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i want to add all the inserted linked list by using this code
but what happens here if i input 15 then 35 =50 but when i input again 30 the sum is 50whats wrong with my code?
but what happens here if i input 15 then 35 =50 but when i input again 30 the sum is 50whats wrong with my code?
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Join Date: Aug 2005
Posts: 15,625
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why is sum a linked list and not a simple integer?
int sum(nd **head){
nd *pl
int sum1 = 0;
p=*head;
while(p!=NULL)
{
sum1 += p->x;
p=p->next;
}
return sum1;
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Originally Posted by Ancient Dragon 
why is sum a linked list and not a simple integer?
int sum(nd **head){ nd *pl int sum1 = 0; p=*head; while(p!=NULL) { sum1 += p->x; p=p->next; } return sum1; }
how about this one where i want to locate if the linked list is in the lis?
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almost there -- the else and return 0 should not be inside the loop. And move p=p->next; to the bottom of the loop.
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Originally Posted by Ancient Dragon
why is sum a linked list and not a simple integer?
int sum(nd **head){ nd *pl int sum1 = 0; p=*head; while(p!=NULL) { sum1 += p->x; p=p->next; } return sum1; }
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Originally Posted by vbcielle
actualy i dont know how to di this ...i tired you code it works
how about this one where i want to locate if the linked list is in the lis?
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nd *p;
p=*head;
while(p!=NULL)
{
p=p->next;
}
if(num==p->x)
return 1;
else
return 0;
}
the code above always return to xero
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Join Date: Aug 2005
Posts: 15,625
Reputation:
Solved Threads: 1495
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Originally Posted by vbcielle
int locate(nd **head,int num){
nd *p;
p=*head;
while(p!=NULL)
{
p=p->next;
}
if(num==p->x)
return 1;
else
return 0;
}
the code above always return to xero
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Originally Posted by Ancient Dragon
Look and think about the logic in the code you posted, pay attention to the while loop. All it does is iterate through the linked list without stopping. The if statement needs to be inside the loop -- I did not tell you to move it outside the loop. The else part shoud not be there at all.
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thankls it work
:cheesy: |
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