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Re: Return Array from C++

May 11th, 2004

•

Originally Posted by tlee

However, my current knowledge does not allow me to see how the pointer can solve this C++ limitation (return a pointer might be dangerous because it might point to the address of local variable, and this variable will go out of scope. Hence, this pointer will point to invalid value). I appreciate for your information.

Pass a pointer to the start as a parameter to the function, and then return this pointer when you're done.

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
#include <iostream>
 
int *foo(int *array)
{
   int *start = array;
   while ( *array )
   {
	  std::cout << *array++ << ' ';
   }
   std::cout << std::endl;
   return start;
}
 
int *bar(int *array)
{
   int *start = array;
   while ( *array )
   {
	  *array++ += 1;
   }
   return start;
}
 
int main()
{
   int myarray[] = {1,2,3,4,5,0};
   foo(bar(foo(bar(foo(myarray)))));
   return 0;
}
 
/* my output
1 2 3 4 5
2 3 4 5 6
3 4 5 6 7
*/
#include <iostream>
 
int *foo(int *array)
{
   int *start = array;
   while ( *array )
   {
	  std::cout << *array++ << ' ';
   }
   std::cout << std::endl;
   return start;
}
 
int *bar(int *array)
{
   int *start = array;
   while ( *array )
   {
	  *array++ += 1;
   }
   return start;
}
 
int main()
{
   int myarray[] = {1,2,3,4,5,0};
   foo(bar(foo(bar(foo(myarray)))));
   return 0;
}
 
/* my output
1 2 3 4 5
2 3 4 5 6
3 4 5 6 7
*/