#include <stdio.h>
#include <math.h>
 
int main()
{
    char ch;//input character
    int ascii;//input's ascii equivalent
    int b,i;
 
    double sum = 0;//You can initilaize it to int but some compilers(like Dev-C++) causes troubles  and generates wrong output...
 
    printf("Enter any character ");
    scanf(" %c",&ch);
 
    ascii = ch;//if you asssign a char to an int, the int variable holds the assigned character's ASCII code
 
 
 
    for(i = 0;; i++)
    {
          b = ascii % 2;//converting binary...
          ascii /= 2;//converting binary...
 
          sum += b * pow(10,i);//variable b's first value is first digit the binary code from right to left
          //so we multiply it by E+0
          printf("%0.lf\n",sum);//Watch how your variable to be converted in ASCII
 
          if(ascii == 1 || ascii == 0) break;//If we divide an integer to 2, we obtain 1 or 0 as a result
          //if we don't control this will be an infinite loop.
 
 
    }
 
    sum += ascii * pow(10,i + 1);//End of our loop we divided the value 2 again and the variable ascii's value was 1
    //so we exit the loop beacause of the if statement and we didn't multiply it E + 6.We are doing this here. 
 
    printf("%0.lf",sum);//Output...
 
 
 
    return 0;
 
}