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Unzip Function
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Hi,
I am writing a function to unzip a zipped file. But I'm getting this error, "Cast from string "C:\temp\FileName.zip" to type 'Integer' is not valid." Below is my coding, I got this error in the bold line. May I know what does the casting error mean here? Why do I need to cast the string of my zip file path to integer?
I am writing a function to unzip a zipped file. But I'm getting this error, "Cast from string "C:\temp\FileName.zip" to type 'Integer' is not valid." Below is my coding, I got this error in the bold line. May I know what does the casting error mean here? Why do I need to cast the string of my zip file path to integer?
ExtractZIPfiles(Directory.GetFiles(strFullDirectoryPath, "*.Zip"))
Private Sub ExtractZIPfiles(ByVal pathList() As String)
Dim x As New ICSharpCode.SharpZipLib.Zip.FastZip
Dim strFullDirectoryPath As String = Path.GetFullPath("C:\temp")
For Each s As String In pathList
x.ExtractZip(pathList(s), strFullDirectoryPath, "csv;xsl")
Next
End Sub
Private Sub ExtractZIPfiles(ByVal pathList() As String)
Dim x As New ICSharpCode.SharpZipLib.Zip.FastZip
Dim strFullDirectoryPath As String = Path.GetFullPath("C:\temp")
For Each s As String In pathList
x.ExtractZip(pathList(s), strFullDirectoryPath, "csv;xsl")
Next
End Sub
hi,
above function's return type may be an integer so u need to declare one variable as integer and rewrite it again as like follows
dim y as int
y=x.ExtractZip(pathList(s), strFullDirectoryPath, "csv;xsl")
it will be execute properly
Dim x As New ICSharpCode.SharpZipLib.Zip.FastZip
Dim strFullDirectoryPath As String = Path.GetFullPath("C:\temp")
For Each s As String In pathList
x.ExtractZip(pathList(s), strFullDirectoryPath, "csv;xsl")
Next
End Sub
hi,
above function's return type may be an integer so u need to declare one variable as integer and rewrite it again as like follows
dim y as int
y=x.ExtractZip(pathList(s), strFullDirectoryPath, "csv;xsl")
it will be execute properly
Last edited by wavalker; Apr 11th, 2007 at 2:32 am.
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Originally Posted by wavalker 
Private Sub ExtractZIPfiles(ByVal pathList() As String)
Dim x As New ICSharpCode.SharpZipLib.Zip.FastZip
Dim strFullDirectoryPath As String = Path.GetFullPath("C:\temp")
For Each s As String In pathList
x.ExtractZip(pathList(s), strFullDirectoryPath, "csv;xsl")
Next
End Sub
hi,
above function's return type may be an integer so u need to declare one variable as integer and rewrite it again as like follows
dim y as int
y=x.ExtractZip(pathList(s), strFullDirectoryPath, "csv;xsl")
it will be execute properly
I've tried your suggestion, it cannot work, because it says the expression
x.ExtractZip(pathList(s), strFullDirectoryPath, "csv;xsl")
does not return a value.
So anymore suggestion?
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So what did you do to solve it?
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This
pathList(s) is evaluated before the ExtractZip method, pathList is an array and requires an integer argument in the parenthesis representing the index number, but string s is being passed instead. •
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Join Date: Aug 2006
Posts: 812
Reputation:
Solved Threads: 13
Practically a Posting Shark
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Originally Posted by hollystyles
This pathList(s) is evaluated before the ExtractZip method, pathList is an array and requires an integer argument in the parenthesis representing the index number, but string s is being passed instead. oh yeah now i get it. Thanks
There is just two ways to live your life.
One is as though nothing is a miracle.
The other is as if everything is.
One is as though nothing is a miracle.
The other is as if everything is.
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Join Date: Feb 2005
Posts: 1,181
Reputation:
Solved Threads: 67
wonder_gal,
as you're new just to let you know, we like to explain solutions as much as possible so that other visitors with similar problems can learn from existing threads instead of starting new ones. Also as you are the owner of this thread you can mark it as solved there is an option on the screen that only you will see, that's also helpful for us to know so we don't waste time reading solved threads.
Thanks for your contribution.
as you're new just to let you know, we like to explain solutions as much as possible so that other visitors with similar problems can learn from existing threads instead of starting new ones. Also as you are the owner of this thread you can mark it as solved there is an option on the screen that only you will see, that's also helpful for us to know so we don't waste time reading solved threads.
Thanks for your contribution.
Last edited by hollystyles; Apr 11th, 2007 at 8:59 am.
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Originally Posted by hollystyles
wonder_gal,
as you're new just to let you know, we like to explain solutions as much as possible so that other visitors with similar problems can learn from existing threads instead of starting new ones. Also as you are the owner of this thread you can mark it as solved there is an option on the screen that only you will see, that's also helpful for us to know so we don't waste time reading solved threads.
Thanks for your contribution.
Icic, I got it. I just marked this post as SOLVED already.
Thanks to everyone here for sharing.
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