so why do u divede by 5 not 3

also it is givin me the wrong output

i need to list the avg of all the students entered with a *** next to the ones with 95% or higher

Because there are five students. The first average taken inside of the loop is the average of a single student's three grades. The second average taken outside of the loop is the average of all five student's averages.

>also it is givin me the wrong output
What's wrong about it?

>i need to list the avg of all the students entered with a *** next to the ones with 95% or higher
We haven't gotten to that part yet. You don't write everything in one swell foop, you write a little and test a little until all of the features are added and working properly.

/*for (x=0; x<2; x++)
{
if (st[x].id == 0)
break;
printf("\n %ld ", st[x].id);
printf("\t %s ", st[x].name);
printf("\t %.1f ", st[x].assignment); //print average instead and *** when >95
} */
double sum = 0;
for (x=0; x<2; x++)
{
double avg = ( st[x].assignment + st[x].quiz1 + st[x].quiz2 ) / 3;
if (st[x].id == 0)
break;
printf("\n %ld ", st[x].id);
printf("\t %s ", st[x].name);
printf("\t %.1f ", avg );
sum += avg;
}
printf ( "\nTotal average: %f\n", sum / 3 );

hey it worked narue yo the man
i figur wat was wrong i had the tot # of student to 25 so i changed it all to 2 and it worked
now how do i place ** next to the ones with 95 %

i relized it was just a simple mistake at teh begging of the code i had set it to 25 studetns but by the time i got to the bottom i just put in a random number of students

now i am done with that how do I add ***
would it be another if statement
such as

else if

I DID ALL BYMYSELF LOL JK NARUE THANK YOU VERY MUCH YOUR GUIDENCE HELPED ALOT
LOOK AT THE OUTCOME
double sum = 0;
for (x=0; x<2; x++)
{
double avg = ( st[x].assignment + st[x].quiz1 + st[x].quiz2 ) / 3;
if (st[x].id == 0)
break;
printf("\n %ld ", st[x].id);
printf("\t %s ", st[x].name);
printf("\t %.1f ", avg );
if (avg > 95)
printf("*****");

sum += avg;
}
printf ( "\nTotal average: %f\n", sum / 3 );
}