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convert string to double, and result is string again
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hello
how to convert string to double, and result is string.
example ;
String code =00000000001;
Double plus =code + 1;
String result =plus; // and result is 0000000002
thanks
how to convert string to double, and result is string.
example ;
String code =00000000001;
Double plus =code + 1;
String result =plus; // and result is 0000000002
thanks
•
•
Join Date: Feb 2007
Posts: 871
Reputation: 
Solved Threads: 7
Practically a Posting Shark
Have this as example.......
class doubconv
{
public static void main(String args[])
{
String code="00000000001";
double dbl=Double.parseDouble(code);
double dbl1=dbl+1;
String result=dbl1+"";
System.out.println(result);
}
}
class doubconv
{
public static void main(String args[])
{
String code="00000000001";
double dbl=Double.parseDouble(code);
double dbl1=dbl+1;
String result=dbl1+"";
System.out.println(result);
}
}
Adios,
Vinod......
Vinod......
•
•
Join Date: Feb 2006
Posts: 2,386
Reputation: 
Solved Threads: 252
Awwwwwwwww, but how do I get the leading zeroes back?! Will be his next post.
Java Programmer and Sun Systems Administrator
----------------------------------------------
Debugging is twice as hard as writing the code in the first place. Therefore, if you write the code as cleverly as possible, you are, by definition, not smart enough to debug it.
--Brian Kernighan
----------------------------------------------
Debugging is twice as hard as writing the code in the first place. Therefore, if you write the code as cleverly as possible, you are, by definition, not smart enough to debug it.
--Brian Kernighan
•
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Join Date: Feb 2007
Posts: 871
Reputation:
Solved Threads: 7
Practically a Posting Shark
if you have better way more than this means please show your solutions also. it will be really useful
(for adding zero)
class doubconv
{
public static void main(String args[])
{
String code="00000000001";
int leng=code.length();
int cnt=0;
for(int j=0;j<leng;j++)
{
char c=code.charAt(j);
if(c=='0')
{
cnt++;
}
else
{
break;
}
System.out.println(cnt);
}
String si="";
for (int k=0;k<cnt ;k++ )
{
si=si+"0";
}
double dbl=Double.parseDouble(code);
double dbl1=dbl+1;
String result=si+dbl1+"";
System.out.println(result);
}
}
(for adding zero)
class doubconv
{
public static void main(String args[])
{
String code="00000000001";
int leng=code.length();
int cnt=0;
for(int j=0;j<leng;j++)
{
char c=code.charAt(j);
if(c=='0')
{
cnt++;
}
else
{
break;
}
System.out.println(cnt);
}
String si="";
for (int k=0;k<cnt ;k++ )
{
si=si+"0";
}
double dbl=Double.parseDouble(code);
double dbl1=dbl+1;
String result=si+dbl1+"";
System.out.println(result);
}
}
Last edited by vinod_javas; Aug 21st, 2007 at 2:59 am.
Adios,
Vinod......
Vinod......
hello,
String s1=new String("0000001");
Double d=new Double(s1);
double d1=d.doubleValue();
s1=d1+"";
if u solve ur problem plz give a reply. i hopw u will solve ur problem by using this simple logic
String s1=new String("0000001");
Double d=new Double(s1);
double d1=d.doubleValue();
s1=d1+"";
if u solve ur problem plz give a reply. i hopw u will solve ur problem by using this simple logic
•
•
Join Date: Feb 2006
Posts: 2,386
Reputation:
Solved Threads: 252
Repeat reply #5.
Java Programmer and Sun Systems Administrator
----------------------------------------------
Debugging is twice as hard as writing the code in the first place. Therefore, if you write the code as cleverly as possible, you are, by definition, not smart enough to debug it.
--Brian Kernighan
----------------------------------------------
Debugging is twice as hard as writing the code in the first place. Therefore, if you write the code as cleverly as possible, you are, by definition, not smart enough to debug it.
--Brian Kernighan
•
•
Join Date: Jun 2006
Posts: 7,617
Reputation:
Solved Threads: 466
I am almost sure that you are doing all this for display purposes. If so, then why not just use the formatting provided by the printf method.
Java Syntax (Toggle Plain Text)
I don't accept change; I don't deserve to live.
That or use NumberFormat.
To any sane person (and a computer in that regard is a sane person) the leading zeros are utterly unimportant, a darned nuisance even, and thus stripped and ignored.
None of you except sos realised that apparently. None of you took the trouble to actually look at how numbers are represented in a computer, and thus realised that there are no leading zeros anywhere.
The number is stored as a series of bits representing a number, NOT a string, and a number never has leading zeros.
To any sane person (and a computer in that regard is a sane person) the leading zeros are utterly unimportant, a darned nuisance even, and thus stripped and ignored.
None of you except sos realised that apparently. None of you took the trouble to actually look at how numbers are represented in a computer, and thus realised that there are no leading zeros anywhere.
The number is stored as a series of bits representing a number, NOT a string, and a number never has leading zeros.
As people are clearly allowed to attack me but I'm not allowed to defend myself, I no longer post to this site.
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