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Join Date: Apr 2007

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rapperhuj

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Else If statement

Sep 6th, 2007

Hello everyone, I just need help on this code. I can't debug it, I'm just new in Java and this is just my fifth assignment so I'm really having a hard time.

Here's my code:

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import java.io.*;
public class input
{
    public static InputStreamReader Reader=new
    InputStreamReader (System.in);
    public static BufferedReader input=new 
    BufferedReader(Reader);
    public static void main(String args[]);
    String name;
    int age;
    double salary;
    {
    System.out.println("Enter name:");
    name=input.readline();
    System.out.println("Enter age:");
    age=Integer.parseInt(input.readLine());
    if(age<=18)
    System.out.println("Too young!");
    }
    else if (age>=18);
    {
    System.out.println("You're ready to vote!");
    }
    }
import java.io.*;
public class input
{
    public static InputStreamReader Reader=new
    InputStreamReader (System.in);
    public static BufferedReader input=new 
    BufferedReader(Reader);
    public static void main(String args[]);
    String name;
    int age;
    double salary;
    {
    System.out.println("Enter name:");
    name=input.readline();
    System.out.println("Enter age:");
    age=Integer.parseInt(input.readLine());
    if(age<=18)
    System.out.println("Too young!");
    }
    else if (age>=18);
    {
    System.out.println("You're ready to vote!");
    }
    }

the Error says that:
illegal start of type line 20
<identifier> expected line 20

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else if (age>=18);
else if (age>=18);

Can anyone please tell me how to debug it? =/

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Ezzaral

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Re: Else If statement

Sep 6th, 2007

Your braces and semicolons are out of place. Look through your if () else if () block and check them.

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rapperhuj

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Re: Else If statement

Sep 6th, 2007

uhmmm.. I'm sorry, but I already tried to move the braces at the "else if" line. Still I can't let it run. =(

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Ezzaral

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Re: Else If statement

Sep 6th, 2007

Look at the structure of your class and main() method and compare that with your other assignments which do run. Also, look at the brace structure of any if-else block. The problems should be reasily apparent to you.

This is about as basic as debugging can get and you need to spot the problems on your own to learn. I've already told you what the nature of the problem is, so all you have to do is look at those blocks.

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rapperhuj

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Re: Else If statement

Sep 6th, 2007

ok.. thx.. I'll check them.. =)

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Re: Else If statement

Sep 6th, 2007

arg.. a new error occured. >.< this is my only notes/guide for the if else statement. =(

 Help with Code Tags 
 Java Syntax (Toggle Plain Text) 
import java.io.*;
public class input{
    public static InputStreamReader Reader=new 
    InputStreamReader(System.in);
    public static BufferedReader input=new 
    BufferedReader(Reader);
    public static void main(String args[]){
    String name;
    int age;
    {
    System.out.println("Enter name:");
    name=input.readLine();
    System.out.println("Enter age:");
    age=Integer.parseInt(input.readLine());
    if (age<=17){
    System.out.println("Too young!");
    } else if(age>=18){
    System.out.println("You're ready to vote!");
    }
    }
    }
}
import java.io.*;
public class input{
    public static InputStreamReader Reader=new 
    InputStreamReader(System.in);
    public static BufferedReader input=new 
    BufferedReader(Reader);
    public static void main(String args[]){
    String name;
    int age;
    {
    System.out.println("Enter name:");
    name=input.readLine();
    System.out.println("Enter age:");
    age=Integer.parseInt(input.readLine());
    if (age<=17){
    System.out.println("Too young!");
    } else if(age>=18){
    System.out.println("You're ready to vote!");
    }
    }
    }
}

The error says:
- unreported exception java.io.IOException; must be caught or
declared to be thrown line 12

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name=input.readLine();
name=input.readLine();

- unreported exception java.io.IOException; must be caught or
declared to be thrown line 14

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 Java Syntax (Toggle Plain Text) 
age=Integer.parseInt(input.readLine());
age=Integer.parseInt(input.readLine());

It seems like my teacher forgot something or I copied the code wrong. =(

Last edited by rapperhuj; Sep 6th, 2007 at 10:48 pm.

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Re: Else If statement

Sep 7th, 2007

I do not know what your teacher gave it to you and if you already covered Exceptions, but that what you get when you use BufferedReader getLine().
Check this tutorial and you should be able to figure it out what to do with it. Main difference between yours code and code in the tutorials is that you read from command line and tutorial do it from a file

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(~100 BC)
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Join Date: May 2007

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Ezzaral

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Re: Else If statement

Sep 7th, 2007

Using Scanner to read the input would be easier and you wouldn't have to mess with the ioexception.
http://java.sun.com/javase/6/docs/ap...l/Scanner.html

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thenava

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Re: Else If statement

Sep 7th, 2007

or just add

throws IOException

underneath your main method declaration.

...
public static void main(String args[])
throws IOException {
String name;
...

that should work.

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Ezzaral

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Re: Else If statement

#10

Sep 7th, 2007

•

Originally Posted by thenava

or just add

throws IOException

underneath your main method declaration.

...
public static void main(String args[])
throws IOException {
String name;
...

that should work.

No, main really should not throw exceptions. How do you intend to handle an exception that is thrown beyond the scope of your execution?

The catch block should be placed within main() and handle the exception gracefully.