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wht will be the o/p?
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Originally Posted by abhishekgahoi 
#include <stdio.h>
int main()
{
int i=5;
printf("%d %d %d %d %d", --i,i--,++i,--i,i);
return 0;
}
Last edited by Aia; Sep 28th, 2007 at 5:32 pm.
"If it moves, tax it. If it keeps moving, regulate it, and if it stops moving, subsidize it" - Ronald Reagan stating how a liberal's mind works.
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Join Date: Aug 2007
Posts: 63
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Junior Poster in Training
it is easy
i is 5
then -- i which means (i) is 4
then i-- which will appear 4 then i will be 3 then
++i which means increase by one so (i) is 4 then
-- i becomes i is 3, then print last (i) which is 3
the result is 4 4 4 3 3
please reply if I am mistaken
i is 5
then -- i which means (i) is 4
then i-- which will appear 4 then i will be 3 then
++i which means increase by one so (i) is 4 then
-- i becomes i is 3, then print last (i) which is 3
the result is 4 4 4 3 3
please reply if I am mistaken
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Join Date: Dec 2005
Posts: 6,601
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> please reply if I am mistaken
You are mistaken.
Read the link Aia posted.
Trying to rationalise what you expect to happen, or merely posting what your current compiler gives you is no way to go.
You are mistaken.
Read the link Aia posted.
Trying to rationalise what you expect to happen, or merely posting what your current compiler gives you is no way to go.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
--
If your code lacks code tags, you will be IGNORED
--
If your code lacks code tags, you will be IGNORED
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Join Date: Aug 2007
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Junior Poster in Training
Thank you I learnt somthing from you
but I was thinking the program will run as
this following:
#include<stdio.h>
int main()
{
int i=5;
printf("%d",--i);
printf("%d",i--);
printf("%d",++i);
printf("%d",--i);
printf("%d",i);
return 0;
}
but I was thinking the program will run as
this following:
#include<stdio.h>
int main()
{
int i=5;
printf("%d",--i);
printf("%d",i--);
printf("%d",++i);
printf("%d",--i);
printf("%d",i);
return 0;
}
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Join Date: Dec 2005
Posts: 6,601
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That would be a completely different program, which is fine.
Use that FAQ to also look up "sequence points". You'll see that each side effect is separated by a sequence point, so there is no issue about the order of things and your program is well defined.
But to say it always has the same output as the one-liner in the original post would be wrong.
Use that FAQ to also look up "sequence points". You'll see that each side effect is separated by a sequence point, so there is no issue about the order of things and your program is well defined.
But to say it always has the same output as the one-liner in the original post would be wrong.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
--
If your code lacks code tags, you will be IGNORED
--
If your code lacks code tags, you will be IGNORED
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Join Date: May 2007
Posts: 1,873
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Solved Threads: 56
Did you run the program before asking?
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Originally Posted by twomers
Did you run the program before asking?
Last edited by Aia; Sep 30th, 2007 at 12:45 pm.
"If it moves, tax it. If it keeps moving, regulate it, and if it stops moving, subsidize it" - Ronald Reagan stating how a liberal's mind works.
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