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Error message!

 
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  #1
Sep 29th, 2007
hey there;
i wanted to write a program to convert binary to decimal.
i did that using the " character approach".
it works just fine.
then i decided to enhance the program by adding an error message whenever the input are invalid (i.e anything other than 0, 1 ), but i havent been able to figure it out yet.
i've been playing around with it but it is still not coming.
my knowledge of C program is very limited ( i've just started learning C).
was wondering if you guys could possibly help me with it.
any help is appreciated!

here is the codes of what i wrote:
C Syntax (Toggle Plain Text) 
  1. #include <stdlib.h>
  2. #include <stdio.h>
  3.  
  4. int main ()
  5. {
  6.     int decimalValue=0;
  7.     int nextDigit;
  8.     char binary;
  9.  
  10.     printf(" Enter Binary Number ! \n");
  11.     binary = getchar();
  12.  
  13.     while (binary == '1' || binary == '0')
  14.           {                 
  15.                if (  binary == '1')
  16.                     { 
  17.                              nextDigit=1;           
  18.                     }
  19.  
  20.                else   
  21.                      {                     
  22.                              nextDigit=0;
  23.                      }      
  24.  
  25.  
  26.  
  27.               decimalValue = decimalValue*2 + nextDigit ; 
  28.               binary = getchar();
  29.  
  30.           }
  31.  
  32.     printf ("The Decimal Value= %i\n", decimalValue);
  33.  
  34.     system("PAUSE");
  35.     return 0;
  36. }
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Re: Error message!

 
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  #2
Sep 29th, 2007
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Originally Posted by megan-smith View Post
hey there;
i wanted to write a program to convert binary to decimal.
i did that using the " character approach".
it works just fine.
then i decided to enhance the program by adding an error message whenever the input are invalid (i.e anything other than 0, 1 ), but i havent been able to figure it out yet.
i've been playing around with it but it is still not coming.
I must be missing something because there seems to be no attempt in the posted code to deal with invalid input. We therefore can't tell what you are doing wrong.
The 3 Laws of the Procrastination Society:
1) Never do today that which can be put off until tomorrow
2) Tomorrow never comes
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Re: Error message!

 
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  #3
Sep 29th, 2007
here's the best i came up with.
but sitll, it doesn't account for invalid numbers which start with 0 or 1 ( ie 123)!
thanks in advance.
C Syntax (Toggle Plain Text) 
  1. #include <stdlib.h>
  2. #include <stdio.h>
  3.  
  4. int main ()
  5. {
  6.     int decimalValue=0;
  7.     int nextDigit;
  8.     char binary;
  9.  
  10.  
  11.     printf("Enter Binary Number ! \n");
  12.     binary = getchar();
  13.  
  14.  
  15.     if (binary > '1' || binary < '0')
  16.           {
  17.               printf("ERROR!  \n");
  18.           }
  19.     else
  20.           {
  21.                     while (binary == '1' || binary == '0')
  22.                           {                 
  23.                                               if (  binary == '1')
  24.                                                     { 
  25.                                                               nextDigit=1;           
  26.                                                     }
  27.  
  28.                                               else   
  29.                                                     {                     
  30.                                                                 nextDigit=0;
  31.                                                     }      
  32.  
  33.  
  34.  
  35.                               decimalValue = decimalValue*2 + nextDigit ; 
  36.                               binary = getchar();
  37.  
  38.  
  39.  
  40.  
  41.  
  42.  
  43.                           }   
  44.  
  45.  
  46.  
  47.  
  48.  
  49.                        printf ("The Decimal Value = %i\n", decimalValue);
  50.  
  51.             }
  52.  
  53.  
  54.  
  55.     system("PAUSE");
  56.     return 0;
  57. }
Last edited by megan-smith; Sep 29th, 2007 at 1:31 am.
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Re: Error message!

 
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  #4
Sep 29th, 2007
Dave's short version: read all user input as the text it is; interpret it at your leisure.
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Re: Error message!

 
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  #5
Sep 29th, 2007
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Originally Posted by Dave Sinkula View Post
Dave's short version: read all user input as the text it is; interpret it at your leisure.
but how?
I read the very first input.
but i'm stuck when it comes to the the second input and third and ....
it would have been great had you explained a bit more.
thanks though.
cheers
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Re: Error message!

 
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  #6
Sep 29th, 2007
Somewhere in section 3.
http://sinkula.homestead.com/files/posts.pdf
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Re: Error message!

 
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  #7
Sep 29th, 2007
> but sitll, it doesn't account for invalid numbers which start with 0 or 1 ( ie 123)!
Maybe put the 'if' statement inside the 'while' loop ?

But separating input from conversion is good as well, as Dave has remarked.
Last edited by Salem; Sep 29th, 2007 at 3:24 am.
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Re: Error message!

 
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  #8
Sep 29th, 2007
putting if statement in the while loop didn't seem to work. at least the way i did it .
Could you please show on the codes what you meant.

how do you seperate the input form the conversion?
the link Dave gave out was way too high-level for me, which i did'nt really understand.
Could you be more explicit and clear.
I told ya.
I'm just beginning.
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Re: Error message!

 
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  #9
Sep 29th, 2007
So post your latest effort, not a description of what you may have tried.
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