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c++ functions to compare numbers
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C++ Syntax (Toggle Plain Text)
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I'd have loved to use your second option, but my professor is very particular about the format of his assignments...
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A few questions narue...what exactly does the '?' do?
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Newbie Poster
? is a statement that following it, there is a choice where can choose the true for the first and the false for the last one else.
Say It Like It Is.
Có sao nói vậy.
Có sao nói vậy.
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Ok thx for your input. still having some problems with the compilation.
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Junior Poster
My C is a little rusty, so I might not have gotten the syntax exactly right, but this should work.
#include <fstream>
#include <iostream>
/* Note: I don't think you need all of the #includes you had. I think that #include <stdio> would be all you need
*/
using namespace std;
int main()
{
int num1 = 0;
int num2 = 0;
char again = 'y';
while (again=='y')
{
getnumbers(&num1, &num2);
if (findbig(num1, num2) < 0)
{
cout<< num2 " is the larger of " num1 " and " num2 "\n";
} else if (findbig(num1, num2) > 0) {
cout<< num1 " is the larger of " num1 " and " num2 endl "\n";
} else {
cout<< "the numbers are the same.\n";
}
cout<<"Go again?(y/n): ";
cin>>again;
}
}
/*
Notice that getnumbers receives the addresses of two ints from the caller. Before returning, it fill in the values, pointed to by the addresses provided int the input parameters.
*/
void getnumbers(int *num1, int *num2)
{
cout<<"Please enter two numbers to compare "<<endl;
cin>>*num1>>*num2;
}
int getbig(int num1, int num2)
{
/* returns -1 if num1 < num2, 0 if equal, +1 if num1 > num2 */
if (num1 < num2) {
return -1;
} else if (num1 > num2) {
return 1;
} else {
return 0;
}
}
#include <fstream>
#include <iostream>
/* Note: I don't think you need all of the #includes you had. I think that #include <stdio> would be all you need
*/
using namespace std;
int main()
{
int num1 = 0;
int num2 = 0;
char again = 'y';
while (again=='y')
{
getnumbers(&num1, &num2);
if (findbig(num1, num2) < 0)
{
cout<< num2 " is the larger of " num1 " and " num2 "\n";
} else if (findbig(num1, num2) > 0) {
cout<< num1 " is the larger of " num1 " and " num2 endl "\n";
} else {
cout<< "the numbers are the same.\n";
}
cout<<"Go again?(y/n): ";
cin>>again;
}
}
/*
Notice that getnumbers receives the addresses of two ints from the caller. Before returning, it fill in the values, pointed to by the addresses provided int the input parameters.
*/
void getnumbers(int *num1, int *num2)
{
cout<<"Please enter two numbers to compare "<<endl;
cin>>*num1>>*num2;
}
int getbig(int num1, int num2)
{
/* returns -1 if num1 < num2, 0 if equal, +1 if num1 > num2 */
if (num1 < num2) {
return -1;
} else if (num1 > num2) {
return 1;
} else {
return 0;
}
}
Last edited by hopalongcassidy; Oct 11th, 2007 at 4:02 pm.
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Newbie Poster
So complexity hi hi ^^. Very complex brain. There are 14 errors and 2 warnings. I only know this.
Say It Like It Is.
Có sao nói vậy.
Có sao nói vậy.
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hopalongcassidy.....welcome aboard and thanks for your input. I made made a bit of modifcations, but seem to be having a little problem. We're almost there. I'm posting both my source code and also the errors that I get. Thanks.
The errors:
C++ Syntax (Toggle Plain Text)
C++ Syntax (Toggle Plain Text)
You have a wayward closing brace here:
>I'd have loved to use your second option, but my professor
>is very particular about the format of his assignments...
I didn't expect you to use it anyway. That was in response to another poster who asked how I might solve the problem for any number of values.
>A few questions narue...what exactly does the '?' do?
It's a conditional operator, roughly equivalent to this:
>but seem to be having a little problem.
Your problems always seem to be strictly syntax based. Programming is all about an eye for detail, C++ programming even more so. You need to understand the rules and follow them. Here are your mistakes. Try to learn what they are, and why you keep making them:
>getnumbers(&num1, &num2)
Semicolons are consistently required. Find out where, and don't forget them.
>cout<< num2<< " is the larger of " <<num1<< " and "<< num2 "\n";
Every << single << individual << item << is << separated << by << an << insertion << operator.
>cout<< num1 <<" is the larger of "<< num1<< " and " <<num2 endl "\n";
Ditto.
An else statement cannot exist without a matching if statement.
C++ Syntax (Toggle Plain Text)
>is very particular about the format of his assignments...
I didn't expect you to use it anyway. That was in response to another poster who asked how I might solve the problem for any number of values.
>A few questions narue...what exactly does the '?' do?
It's a conditional operator, roughly equivalent to this:
C++ Syntax (Toggle Plain Text)
Your problems always seem to be strictly syntax based. Programming is all about an eye for detail, C++ programming even more so. You need to understand the rules and follow them. Here are your mistakes. Try to learn what they are, and why you keep making them:
>getnumbers(&num1, &num2)
Semicolons are consistently required. Find out where, and don't forget them.
>cout<< num2<< " is the larger of " <<num1<< " and "<< num2 "\n";
Every << single << individual << item << is << separated << by << an << insertion << operator.
>cout<< num1 <<" is the larger of "<< num1<< " and " <<num2 endl "\n";
Ditto.
C++ Syntax (Toggle Plain Text)
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Junior Poster
I told you that my C is a little rusty. It looks like I should have put a ; after the call to getnumbers() and removed the endl. If you want to make those changes and try it again, it should reduce the number of error messages from the compiler.
I don't have a C compiler on the machine I'm using right now or I'd verify it myself.
I don't have a C compiler on the machine I'm using right now or I'd verify it myself.
Last edited by hopalongcassidy; Oct 11th, 2007 at 5:46 pm.
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