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operator overload
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Hi
when I look at this website http://www.parashift.com/c++-faq-lit...erloading.html,
I don't quite understand for the section 13.14 about prefix++ and postfix++.
Number x = /* ... */;
++x; // calls Number::operator++(), i.e., calls x.operator++()
x++; // calls Number::operator++(int), i.e., calls x.operator++(0)
why ++x is calling x.operator++() while x++ is calling calls x.operator++(0)?
when I look at this website http://www.parashift.com/c++-faq-lit...erloading.html,
I don't quite understand for the section 13.14 about prefix++ and postfix++.
Number x = /* ... */;
++x; // calls Number::operator++(), i.e., calls x.operator++()
x++; // calls Number::operator++(int), i.e., calls x.operator++(0)
why ++x is calling x.operator++() while x++ is calling calls x.operator++(0)?
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Join Date: Apr 2006
Posts: 5,051
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This is the important part:
In other words, if one didn't have a dummy int, there'd be no way to disambiguate them.
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Since the prefix and postfix ++ operators can have two definitions, the C++ language gives us two different signatures. Both are called operator++(), but the prefix version takes no parameters and the postfix version takes a dummy int.
"Technological progress is like an axe in the hands of a pathological criminal."
All my posts may be freely redistributed under the terms of the MIT license.
All my posts may be freely redistributed under the terms of the MIT license.
If you would have been given an options to implement operator++() which would work for both versions of ++, how would you do it?
You need to find some way to distinguish between both of them.
You need to find some way to distinguish between both of them.
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Join Date: Oct 2006
Posts: 222
Reputation:
Solved Threads: 14
Posting Whiz in Training
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Number x = /* ... */;
++x; // calls Number::operator++(), i.e., calls x.operator++()
x++; // calls Number::operator++(int), i.e., calls x.operator++(0)
That IS the overload method.
As they say: "It is what it is."
You looked it up, NOW YOU KNOW...
"I like beating by head against the wall because it feels so good when I stop"
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