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How???

 
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  #1
Mar 10th, 2008
How to count> Is true I do this programming?

C++ Syntax (Toggle Plain Text) 
  1.  
  2. {
  3. int count;
  4. count=0;
  5. count++;
  6.  for ( int i = 0 ; i < students.size (); i++ )
  7. {
  8. for ( int k = 0;k<students.at(i).examcode.size(); k++ )
  9. {
  10. if (students.at (i).examcode.at(0)=0)
  11. {
  12. cout<<count++<< " ";
  13. }
  14. }
  15. }
  16. }
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Re: How???

 
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  #2
Mar 10th, 2008
What are you trying to count? Number of examcodes for each student?

line 10: you want to use the == operator there, not the assignment = operator.
Last edited by Ancient Dragon; Mar 10th, 2008 at 11:31 pm.
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Re: How???

 
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  #3
Mar 11th, 2008
I want to count how many (3,13) appear..is it like this?

c++ Syntax (Toggle Plain Text) 
  1. {
  2. int count;
  3. count=0;
  4. count++;
  5. for ( int i = 0 ; i < students.size (); i++ )
  6. {
  7. {
  8. for ( int k = 1;k<students.at(i).examcode.size(); k++ )
  9. if (students.at (i).examcode.at(0)==3)	
  10. {
  11. cout<<"  "<< count++;
  12. }
  13. if (students.at (i).examcode.at(k)==13)	
  14. {
  15. cout<< " " <<count++;
  16. }
  17. }
  18. }
  19. cout <<"\n";
  20. }
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Re: How???

 
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  #4
Mar 11th, 2008
You should increment count only inside the second if statement.
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Re: How???

 
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  #5
Mar 11th, 2008
Is it true to make a condition statement? &&

C++ Syntax (Toggle Plain Text) 
  1. int count;
  2. count++;
  3. for ( int i = 0 ; i < students.size (); i++ )
  4. {
  5. for ( int k = 1;k<students.at(i).examcode.size(); k++ )
  6. {
  7. if (students.at (i).examcode.at(0)==1 && students.at (i).examcode.at(k)==1)	
  8. {
  9. count++;
  10. }
  11. }
  12. }
  13. cout<<"(1,1)="<<count;
  14. cout <<"\n";
  15. cout <<"\n";
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Re: How???

 
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  #6
Mar 12th, 2008
yes that would work, thought you don't need to bracket a single statement under an if() ie
C++ Syntax (Toggle Plain Text) 
  1. if(1 == 1)
  2. {
  3.      return true;
  4. }
is the same as
C++ Syntax (Toggle Plain Text) 
  1. if(1 == 1)
  2.    return true;
you only need curly brackets if more than one piece needs execution
C++ Syntax (Toggle Plain Text) 
  1. if(1 == 1)
  2. {
  3.     cout << "One does equal one";
  4.     return true;
  5. }

also you can use
C++ Syntax (Toggle Plain Text) 
  1. cout << "\n\n";
instead of
C++ Syntax (Toggle Plain Text) 
  1. cout << "\n";
  2. cout << "\n";
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Re: How???

 
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  #7
Mar 12th, 2008
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Originally Posted by nurulshidanoni View Post
Is it true to make a condition statement? &&

C++ Syntax (Toggle Plain Text) 
  1. int count;
  2. count++;
  3. for ( int i = 0 ; i < students.size (); i++ )
  4. {
  5. for ( int k = 1;k<students.at(i).examcode.size(); k++ )
  6. {
  7. if (students.at (i).examcode.at(0)==1 && students.at (i).examcode.at(k)==1)	
  8. {
  9. count++;
  10. }
  11. }
  12. }
  13. cout<<"(1,1)="<<count;
  14. cout <<"\n";
  15. cout <<"\n";
That will not work. You have to increment count only inside the second if like ithelp said. Also initialize count to 0 in line 2.
Last edited by hammerhead; Mar 12th, 2008 at 9:46 am.
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Re: How???

 
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  #8
Mar 12th, 2008
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Originally Posted by hammerhead View Post
That will not work. You have to increment count only inside the second if like ithelp said. Also initialize count to 0 in line 2.
there is no second if statement in the second lot of code, if he uses the current double conditional it should work fine(if count is properly init'ed to 0 as you said).
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Re: How???

 
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  #9
Mar 12th, 2008
^ Sorry my fault.
There are 10 types of people in the world, those who understand binary and those who don't.

All generalizations are wrong. Even this one.
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