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function in php

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•

Join Date: Mar 2008

Posts: 145

Reputation: queenc is an unknown quantity at this point

Solved Threads: 4

queenc

Offline

Junior Poster

function in php

Mar 28th, 2008

hi,

this is a simple program it is not working...please do tell me whether my code is correct

 Help with Code Tags 
 PHP Syntax (Toggle Plain Text) 
<form>
<?php
function login()
{
 print "<script>";
print " window.location='http://www.webs.com/hi.html'";
 print "</script>";  
}
print "<input type='button' name='butt' value='Apply Online' onClick=login() style='height :2em; width :7em; font-weight:bold; font-size:0.7em' >";
?>
</form>
<form>
<?php
function login()
{
 print "<script>";
print " window.location='http://www.webs.com/hi.html'";
 print "</script>";  
}
print "<input type='button' name='butt' value='Apply Online' onClick=login() style='height :2em; width :7em; font-weight:bold; font-size:0.7em' >";
?>
</form>

•

Join Date: Nov 2007

Posts: 86

Reputation: sagedavis is an unknown quantity at this point

Solved Threads: 6

sagedavis

Offline

Junior Poster in Training

Re: function in php

Mar 28th, 2008

you can't call a php function with an onClick event.. onClick is a javascript/DHTML item.

You also don't even need any of the php opening and closing stuff.
Why cause php to print javascript and html items if you already have form tags outside of the scope of the php?

 Help with Code Tags 
 PHP Syntax (Toggle Plain Text) 
<script>
function login(){
window.location='http://www.webs.com/hi.html';
}
</script>
<form>
<input type='button' name='butt' value='Apply Online' onClick='login();' style='height :2em; width :7em; font-weight:bold; font-size:0.7em' >
</form>
<script>
function login(){
window.location='http://www.webs.com/hi.html';
}
</script>
<form>
<input type='button' name='butt' value='Apply Online' onClick='login();' style='height :2em; width :7em; font-weight:bold; font-size:0.7em' >
</form>

Should do the trick.
Although, you really don't even need any of that stuff.
You are just wanting people to go to another page to fill out an application.
This is easily done in html

Help with Code Tags

PHP Syntax (Toggle Plain Text)

<a href="http://www.webs.com/hi.html"><img src="button.gif" /></a>

Sage

•

Join Date: Nov 2007

Posts: 107

Reputation: kings has a little shameless behaviour in the past

Solved Threads: 2

kings

Offline

Junior Poster

Re: function in php

Mar 28th, 2008

no if he is a registered user i want to redirect him to page1.php page or else page2.php...so i taught something like this will help me

•

Join Date: Nov 2007

Posts: 86

Reputation: sagedavis is an unknown quantity at this point

Solved Threads: 6

sagedavis

Offline

Junior Poster in Training

Re: function in php

Mar 29th, 2008

ok, you still can't call a php function on a javascript event, which is what your code is trying to do.

What you need to do is use your php to print out the html code but make the onclick event itself the value.

Something like this.

 Help with Code Tags 
 PHP Syntax (Toggle Plain Text) 
<?PHP
if ($user == $registered){
$onclick = "window.location='http://www.webs.com/page1.html'";
}
else {
$onclick = "window.location='http://www.webs.com/page2.html'";
}
?>
</script>
<form>
<input type='button' name='butt' value='Apply Online' onClick='
<?php echo $onclick; ?>
' style='height :2em; width :7em; font-weight:bold; font-size:0.7em' >
</form>
<?PHP
if ($user == $registered){
$onclick = "window.location='http://www.webs.com/page1.html'";
}
else {
$onclick = "window.location='http://www.webs.com/page2.html'";
}
?>
</script>
<form>
<input type='button' name='butt' value='Apply Online' onClick='
<?php echo $onclick; ?>
' style='height :2em; width :7em; font-weight:bold; font-size:0.7em' >
</form>

Obviosly you will replace user and registered with whatever you use to check users registration...