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Views: 488 | Replies: 10 | Solved
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Join Date: Dec 2007
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Posting Whiz
I use an array for the first time in a while loop without declaring it(as php does not need it)
As the while loop is repeating it increases the number of the array.
Am I doing this right?
Should I have before the loop some code like:
Dont know abit confused and lost.
Thanks, Regards X
syntax Syntax (Toggle Plain Text)
As the while loop is repeating it increases the number of the array.
Am I doing this right?
Should I have before the loop some code like:
syntax Syntax (Toggle Plain Text)
Dont know abit confused and lost.
Thanks, Regards X
Last edited by OmniX : May 9th, 2008 at 4:40 am.
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Join Date: Nov 2007
Location: Bangalore, India
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As you have already said it yourself, you don't have to explicitly declare a variable as an array to use it like an array. You can simply use $var[] = "value"; This will treat $var as an array. But, its always a good practice to initialize a variable before using it. (But most of them don't do it 
)
) Programming today is a race between software engineers striving to build bigger and better idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far, the Universe is winning.
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Posting Whiz
Nav to the rescue again!
Umm nav I can declare it but I cant initialize it as I dont want to give it a value till used in the while loop, so.
What code would I use?
$var[];
?
Umm nav I can declare it but I cant initialize it as I dont want to give it a value till used in the while loop, so.
What code would I use?
$var[];
?
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Join Date: Nov 2007
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php Syntax (Toggle Plain Text)
But, you can't use a normal variable to act like an array. Example,
php Syntax (Toggle Plain Text)
Programming today is a race between software engineers striving to build bigger and better idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far, the Universe is winning.
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Posting Whiz
Ya nav that what I have, but I cant seem to print the $var variable should just be print/print_r/echo $var; but none of it works...
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Why ? print_r($arrayname) should work fine.
Programming today is a race between software engineers striving to build bigger and better idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far, the Universe is winning.
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Posting Whiz
Its being stupid, in short.
It wont let me declare the array before the html, I thought it was possible?
Anyways I have found another way to do it, just need a questions answered.
[code syntax="php"]
while($row = mysql_fetch_array($result)) {
//then to release after it is used so you can reuse it is?
mysql_free_result($result);
[/code]
This correct, Thanks.
It wont let me declare the array before the html, I thought it was possible?
Anyways I have found another way to do it, just need a questions answered.
[code syntax="php"]
while($row = mysql_fetch_array($result)) {
//then to release after it is used so you can reuse it is?
mysql_free_result($result);
[/code]
This correct, Thanks.
Last edited by OmniX : May 9th, 2008 at 7:25 am.
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When you execute a query, a resource identifier will be assigned to $result. mysql_free_result will free this value.
Programming today is a race between software engineers striving to build bigger and better idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far, the Universe is winning.
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Posting Whiz
Allowing me to reuse the query again or in other words fetch it again?
Man nav php can be so annoying at times I fix one error and a new error pops up. I throw the arrays in a forloop and now more errors
. Ill get back to debuging and keep you posted to see if anything works.
PS: can you run queries in a for loop? That could be a possible error? or declare it differently?
Man nav php can be so annoying at times I fix one error and a new error pops up. I throw the arrays in a forloop and now more errors
. Ill get back to debuging and keep you posted to see if anything works.PS: can you run queries in a for loop? That could be a possible error? or declare it differently?
Last edited by OmniX : May 9th, 2008 at 8:22 am.
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I don't know whats causing the error. You can run queries in a for loop. Once you have freed the result using mysql_free_result, that resource identifier is freed. Actually, if your query isn't too complicated, you don't have to use free_result as php frees the result at the end of execution of the script. Source: http://nl3.php.net/mysql_free_result
Can you post your code here ?
Can you post your code here ?
Programming today is a race between software engineers striving to build bigger and better idiot-proof programs, and the Universe trying to produce bigger and better idiots. So far, the Universe is winning.
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