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passing function as a parameter to another function
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Join Date: Jan 2008
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Junior Poster in Training
Hi all,
Do u have any idea that whether I can pass any function as a parameter to another function?
like:
What do you think is this correct (it gave lots of compiling error)...If not is there any other method to do such thing?
Do u have any idea that whether I can pass any function as a parameter to another function?
like:
C++ Syntax (Toggle Plain Text)
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Join Date: Aug 2005
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C++ Syntax (Toggle Plain Text)
C++ Syntax (Toggle Plain Text)
Don't PM me with questions -- you might get a nasty PM in response. If you have a question then post it in one of the forums.
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Junior Poster in Training
hey I tried this one also:
but i got following compile errors
bekar.cpp is filename)
What is wrong with the compiler????
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bekar.cpp is filename) C++ Syntax (Toggle Plain Text)
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Junior Poster in Training
btw thanx for your fast reply.
this: int (*fn)() is declaring fn as a pointer to a function which takes no parameters and returns an int.
But in your code you still refer to it as add(), you need to call fn().
Function points are a nice, but can get complex in C++. An other option would be 'Functor' classes (classes which override the () operator) which would do a similar thing.
But in your code you still refer to it as add(), you need to call fn().
Function points are a nice, but can get complex in C++. An other option would be 'Functor' classes (classes which override the () operator) which would do a similar thing.
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All the above, plus: try is a keyword in c++ (try...catch) so you might want to rename the function to something else.
Hi,
You cannot use try as a function name in c++, because try is a keyword in c++ used for exception handling.
The following code should work.
#include<iostream>
#include<fstream>
#include<vector>
using namespace std;
int i=5,j=8, n= 10;
int (fn)();
int add()
{
int c=i+j;
cout<<c;
return c;
}
int sub()
{
int c=j-i;
cout<<c;
return c;
}
int ans(int (*fn)() )
{
if( add() )
sub();
}
int main()
{
ans(add);
return 0;
}
You cannot use try as a function name in c++, because try is a keyword in c++ used for exception handling.
The following code should work.
#include<iostream>
#include<fstream>
#include<vector>
using namespace std;
int i=5,j=8, n= 10;
int (fn)();
int add()
{
int c=i+j;
cout<<c;
return c;
}
int sub()
{
int c=j-i;
cout<<c;
return c;
}
int ans(int (*fn)() )
{
if( add() )
sub();
}
int main()
{
ans(add);
return 0;
}
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Join Date: Jan 2008
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Junior Poster in Training
so far so gud thanx the program ran....
but I have one question....
pointer to a variable means a thing which points to the variable i.e.it stores the address of the variable...right?
What does pointer to a function imply?
a variable which is pointer to a function stores the address of the function????
but the function is made at run time...correct me if I am wrong?
but I have one question....
pointer to a variable means a thing which points to the variable i.e.it stores the address of the variable...right?
What does pointer to a function imply?
a variable which is pointer to a function stores the address of the function????
but the function is made at run time...correct me if I am wrong?
go through this links. This will clear you all about function pointers.
1,, http://www.newty.de/fpt/index.html
2, http://www.cprogramming.com/tutorial...-pointers.html
1,, http://www.newty.de/fpt/index.html
2, http://www.cprogramming.com/tutorial...-pointers.html
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