Now that I think about it, you probably don't want to simply use Math.sin(i) in your statement.

This means that you're going to go around the circle VERY fast as i increments. Your wavelength will most likely be small unless you use some kind of scalar that multiplies by the sin function (like 50 or so).

If anything, think about how many sin cycles you want in 1000 increments.

Let's say you want 4 cycles (where a cycle is simply 360 degrees (or 2pi radians) reached). Then you'd have to find out when your number reaches a cycle and multiply by that value.

final double CYCLE = 4
final double MAX = 1000

math.sin( ((i + 2)* Math.pi * CYCLE) / ( MAX) ) for the second y arg, and most likely
math.sin(((i) * Math.pi * CYCLE)/ MAX) for the first y arg.