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Views: 169 | Replies: 4
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Join Date: May 2008
Location: Hyderabad,India
Posts: 89
Reputation: 
Rep Power: 1
Solved Threads: 0
Junior Poster in Training
Hi,
I wanted to display data which is in my db.The format of displaying must be in a div, in that div 3 columns & each column must have 10 rows.Am using this:
which is displaying it in a single line. I used even for loop which is displaying again in the single line.What way can be used to print in the above format?
I wanted to display data which is in my db.The format of displaying must be in a div, in that div 3 columns & each column must have 10 rows.Am using this:
while($data = mysql_fetch_array($result)) {
echo $query;
echo ' <tr> <td colspan="3" > <a href="'.$data['MedName'].'" >' . $data['dispname'].' </a> </td>';
echo'</tr>';
} Suhasini
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Join Date: Jun 2007
Location: Valley Center, Kansas
Posts: 554
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Rep Power: 3
Solved Threads: 57
Posting Pro
here is something i typed up a few weeks ago. it should work.
$table = '<table id="module" class="module" border="0" cellspacing="0" cellpadding="5">';
$cols = 3;
$per_column = 10;
$col = 1;
$table .= '<tr>';
$table .= '<td>';
$table .= '<table id="module" class="module" border="0" cellspacing="0" cellpadding="5">';
$i = 0;
while ($row = $p->fetchAssoc($query)) {
$table .= '<tr>';
$table .= '<td><a href="' . $row['MedName'] . '">' . $row['dispname'] . '</a></td>';
$table .= '</tr>';
if ($i == ($per_column*$col)) {
$table .= '</table>';
$table .= '</td>';
$table .= '<td>';
$table .= '<table id="module" class="module" border="0" cellspacing="0" cellpadding="5">';
$col++;
}
$i++;
}
$table .= '</table>';
$table .= '</td>';
$table .= '</tr>';
$table .= '</table>';
echo $table; Last edited by kkeith29 : Jun 4th, 2008 at 3:30 am.
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Join Date: May 2008
Location: Hyderabad,India
Posts: 89
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Rep Power: 1
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Junior Poster in Training
what is $p here
while ($row = $p->fetchAssoc($query))
Suhasini
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Join Date: Jun 2007
Location: Valley Center, Kansas
Posts: 554
Reputation:
Rep Power: 3
Solved Threads: 57
Posting Pro
my bad, use to my class is use. change that to mysql_fetch_assoc($query)
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Join Date: May 2008
Location: Hyderabad,India
Posts: 89
Reputation:
Rep Power: 1
Solved Threads: 0
Junior Poster in Training
Its Working.But have small problem, I have 4 buttons Home Categories Brand Store in a row.When I click each button the text display.Here if catogery is clicked that is in the same row but remaining 3 buttons are moving down.when it is clicked again..they are going back to normal position.Why is it like that?
Suhasini
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