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Views: 639 | Replies: 7
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Join Date: Jul 2008
Posts: 31
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Light Poster
Is there any way how i could compare arrays like pattern matching or should i write my own code?
Thanks.
Thanks.
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Join Date: Jun 2007
Posts: 78
Reputation:
Rep Power: 2
Solved Threads: 6
Junior Poster in Training
Hi,
You can use Like Operator or StrComp Function for Pattern Matching in Array Variable or any other Variable. You can compare the Values like below Given:
1) Bring the Array Values in loop and check the Value like this
IF a(I) LIKE "*a*" THEN
-----
-----
END IF
You can refer more about the Like Operator in
http://msdn.microsoft.com/en-us/libr...xw(VS.71).aspx
2) You can use StrComp Function like this
IF StrComp(a(I), "a") THEN
-----
-----
END IF
Shailaja
You can use Like Operator or StrComp Function for Pattern Matching in Array Variable or any other Variable. You can compare the Values like below Given:
1) Bring the Array Values in loop and check the Value like this
IF a(I) LIKE "*a*" THEN
-----
-----
END IF
You can refer more about the Like Operator in
http://msdn.microsoft.com/en-us/libr...xw(VS.71).aspx
2) You can use StrComp Function like this
IF StrComp(a(I), "a") THEN
-----
-----
END IF
Shailaja
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Originally Posted by Teropod 
Is there any way how i could compare arrays like pattern matching or should i write my own code?
Thanks.
•
•
Join Date: Jul 2008
Posts: 31
Reputation:
Rep Power: 1
Solved Threads: 6
Light Poster
And there is no way to find "pattern" of one array in other? something like a(0) = b, a(1) = c and b(0) = a, b(1) = b, b(2) = c, b(3) = d.
bool = a like *b*
???
bool = a like *b*
???
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Join Date: Jun 2007
Posts: 78
Reputation:
Rep Power: 2
Solved Threads: 6
Junior Poster in Training
hi,
You can do like below when using the variable instead of values.
IF a(0) like "*" & b & "*" THEN
-----------
-----------
END IF
Shailaja
You can do like below when using the variable instead of values.
IF a(0) like "*" & b & "*" THEN
-----------
-----------
END IF
Shailaja
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Originally Posted by Teropod
And there is no way to find "pattern" of one array in other? something like a(0) = b, a(1) = c and b(0) = a, b(1) = b, b(2) = c, b(3) = d.
bool = a like *b*
???
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Join Date: Jul 2008
Posts: 31
Reputation:
Rep Power: 1
Solved Threads: 6
Light Poster
Private Sub Command1_Click()
Dim A(2) As String
Dim B(4) As String
A(0) = 3
A(1) = 2
A(2) = 67
B(0) = 89
B(1) = 3
B(2) = 2
B(3) = 67
B(4) = 99
If A(0) Like "*" & B & "*" Then
MsgBox "ahoy"
End If
End SubIt looks like ill have to use loops, because these is not working. And i don't need one value i need to find is one entire dimension of array in other. I am afraid loops will last too long.
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Originally Posted by manoshailu
hi,
You can do like below when using the variable instead of values.
IF a(0) like "*" & b & "*" THEN
-----------
-----------
END IF
Shailaja
Last edited by Teropod : Jul 18th, 2008 at 3:11 am.
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Join Date: Jun 2007
Posts: 78
Reputation:
Rep Power: 2
Solved Threads: 6
Junior Poster in Training
hi,
Array can be used only by loops and that could be very if u understand wel.
Try the below coding and if you have any doubts in below codings you can ask me i will explain u in detail.
In Below coding, i had used nested loop (i.e). Loop is nothing but Loop is to make a rotation until it gets the end value. If it is Nested Loop then 2 loops used (i.e)
For i = 0 to 10 'Outer Loop
For j = 0 to 5 'Inner Loop
---------
Next
Next
Outer Loop have the value and comes to the inner loop. Then the inner loop starts the rotation until it getting the end value after that move to the outer loop and goes on until the outer loop ends. Simply we can say one element of outer loop compare with all element in the inner loop.
If u understand the loop concept clearly then only u can do anything in any language.
[quote=Teropod;650258]
Shailaja
Array can be used only by loops and that could be very if u understand wel.
Try the below coding and if you have any doubts in below codings you can ask me i will explain u in detail.
In Below coding, i had used nested loop (i.e). Loop is nothing but Loop is to make a rotation until it gets the end value. If it is Nested Loop then 2 loops used (i.e)
For i = 0 to 10 'Outer Loop
For j = 0 to 5 'Inner Loop
---------
Next
Next
Outer Loop have the value and comes to the inner loop. Then the inner loop starts the rotation until it getting the end value after that move to the outer loop and goes on until the outer loop ends. Simply we can say one element of outer loop compare with all element in the inner loop.
If u understand the loop concept clearly then only u can do anything in any language.
[quote=Teropod;650258]
Private Sub Command1_Click() Dim A(2) As String Dim B(4) As String Dim intI as Integer 'intI Variable for A() Dim intj as Integer 'intJ Variable for B() A(0) = 3 A(1) = 2 A(2) = 67 B(0) = 89 B(1) = 3 B(2) = 2 B(3) = 67 B(4) = 99 'Nested Loop For intI = 0 to Ubound(A) For intJ = 0 to Ubound(B) 'Loop works until the size of the B() Array If A(intI) Like "*" & B(intJ) & "*" Then 'A() compared with the all element in the B() MsgBox A(intI) End If Next Next End Sub
Shailaja
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Originally Posted by Teropod
Private Sub Command1_Click() Dim A(2) As String Dim B(4) As String A(0) = 3 A(1) = 2 A(2) = 67 B(0) = 89 B(1) = 3 B(2) = 2 B(3) = 67 B(4) = 99 If A(0) Like "*" & B & "*" Then MsgBox "ahoy" End If End Sub
It looks like ill have to use loops, because these is not working. And i don't need one value i need to find is one entire dimension of array in other. I am afraid loops will last too long.
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Join Date: Jul 2008
Posts: 31
Reputation:
Rep Power: 1
Solved Threads: 6
Light Poster
Tanks but i wanted to avoid that because i am using 3d arrays with 100+ values per one i was hoping i could do it faster.
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Join Date: Jun 2007
Posts: 78
Reputation:
Rep Power: 2
Solved Threads: 6
Junior Poster in Training
Hi,
Try this one. I think this may be useful to u.
To Know more
http://www.vb6.us/tutorials/vb-strin...it-join-filter
Shailaja
Try this one. I think this may be useful to u.
Private Sub Command1_Click()
Dim A(2) As String
Dim B(4) As String
Dim C as String
A(0) = 3
A(1) = 2
A(2) = 67
B(0) = 89
B(1) = 3
B(2) = 2
B(3) = 67
B(4) = 99
IF UBound(Filter(B, A(0), True, vbTextCompare)) >-1 THEN
C=Filter(B, A(0), True, vbTextCompare)
MsgBox C(0)
End If
End Sub
To Know more
http://www.vb6.us/tutorials/vb-strin...it-join-filter
Shailaja
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Originally Posted by Teropod
Tanks but i wanted to avoid that because i am using 3d arrays with 100+ values per one i was hoping i could do it faster.
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