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two letters = one number?

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Join Date: Jul 2008

Posts: 38

Reputation: plike922 is an unknown quantity at this point

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plike922

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two letters = one number?

Jul 20th, 2008

I am wonder how do you make it that you have to letters = to one number with only typing it once? Here is my program. My problem is that the result printf("%d reversed is: %d\n",num , res); is 0 reversed is: (The number backwords).

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#include <iostream>
#include <stdio.h>
#include "simpio.h"
#include "strlib.h"
#include "random.h"
using namespace std;

int main(void)
{
	int num, res=0, rem;
	printf("Please enter an integer: ");
	num = GetInteger();
	while(num > 0)
	
{
rem=num% 10;
res=res* 10 + rem;
num=num/10;
}
printf("%d reversed is: %d\n",num , res);
system("pause");
}

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Join Date: May 2008

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Reputation: adarshcu is an unknown quantity at this point

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adarshcu

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Re: two letters = one number?

Jul 20th, 2008

since this is a c program.
u cannot use iostream.h
and namespaces.
remove the 2 of them anf check it out.

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Join Date: Nov 2005

Posts: 251

Reputation: dwks has a spectacular aura about

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dwks

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Re: two letters = one number?

Jul 22nd, 2008

You could save the numbers as you find them instead of printing them, say in a char array, and then print that array in reverse. On the other hand, it would probably be better to use a different algorithm.

What you need to do is find the most significant (highest and leftmost) digit first. To do this, you'll need to skip over the digits to the right first . . . .

Here's how you can do it.

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 c Syntax (Toggle Plain Text) 
#include <stdio.h>
 
int main() {
    int num = 1234;
    int digit = 1;
 
    if(!num) printf("0\n");
    else {
        while(digit < (num / 10)) digit *= 10;
 
        do {
            printf("%d", (num / digit) % 10);
            digit /= 10;
        } while(digit);
 
        printf("\n");
    }
 
    return 0;
}
#include <stdio.h>

int main() {
    int num = 1234;
    int digit = 1;

    if(!num) printf("0\n");
    else {
        while(digit < (num / 10)) digit *= 10;

        do {
            printf("%d", (num / digit) % 10);
            digit /= 10;
        } while(digit);

        printf("\n");
    }

    return 0;
}

It's just a matter of finding the leftmost digit and starting there, instead of starting at the right . . . .

Last edited by dwks; Jul 22nd, 2008 at 6:44 pm.

dwk

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