Yay! It works now! <333 Thanks for your help, everyone! =)

But... what is an undefined index? o.O; Because now it's giving me that as a notice. Does that just mean it's going to give me that because I don't have any information for the database?

I'm not sure where that error is coming from ... is it a mysql error message?

It could be from the connect.php included file, or it could be caused by the database table structure (?maybe) ... have you got anymore info on that error?

The first thing that popped to mind was you need to pass NULL to the database table for the table unique key iterator to populate that key field, if a default value is not set for that field ... but that's just a wild guess.

:-)

try this code; gope this can help you, that's power only i got. im newbie in php to,

<?php
include ('connect.php');
?>

<form name="form1" method="post" action="dogstore.php">
Dog's Name:
<input name="dogname" type="text">
<br>
Dog's Breed:
<select name="dogbreed">
<option value="breed1">Breed</option>
<option value="breed2">Breed</option>
<option value="breed3">Breed</option>
<option value="breed4">Breed</option>
<option value="breed5">Breed</option>
<option value="breed6">Breed</option>
<option value="breed7">Breed</option>
</select>
<br>
Dog's Gender:
<select name="doggender">
<option value="Male">Male</option>
<option value="Female">Female</option>
</select>
<br>
<input type="submit" name="Submit" value="Buy Dog">
</form>

<?php
//trim removes the white spaces from the beginning and end of the text
$dogname = trim($_POST['dogname']);
$dogbreed = trim($_POST['dogbreed']);
$doggender = trim($_POST['doggender']);

//Make sure the name form is filled out.
if (isset($_POST['dogname'])) {
echo "good";
}
else {

echo "Oops! You forgot to fill in the name!";
}

$ownerid = $_SESSION['id'];

if (!isset($_POST['Buy Dog'])) {
echo "Congratulations! You've purchased a dog.";
}
else {
echo "Congratulations! You've purchased a dog.";
}
$dog = @mysql_query("INSERT INTO dogs (ownerid, dogname, dogbreed, doggender)
VALUES ('$ownerid', '$dogname', '$doggender')") or die("Error:
".mysql_error());
?>