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problem with strtok()

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problem with strtok()

 
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  #1
Aug 19th, 2008
Hi All,

I am facing a problem with using the function strtok(). Following is just a sample code.
The code below stores the string str delimited by comma into an array.

I want to modify the code below so that array would contain an empty space/new line if a value is missing.

i.e., if str[] = source, desti, string1,,string3 ; then my array should hold an empty space/ new line in place of string2.

Can somebody help me with this?
Thanks in Advance

c Syntax (Toggle Plain Text) 
  1. #include <stdio.h>
  2. #include <conio.h>
  3. #include <string.h>
  4.  
  5. main() 
  6. {
  7. 	char str[] = "source,desti,string1,string2,string3";
  8. 	char delims[] = ",";
  9. 	char *result = NULL;
  10. 	char myArray[10][50],*p;
  11.  
  12.  
  13. 	result = strtok( str, delims );
  14.  
  15. 	while( result != NULL ) 
  16. 	{
  17. 		printf( "%s \n", result );
  18. 		result = strtok( NULL, delims );
  19. 	}
  20.  
  21.        getch();
  22.  
  23. }
Last edited by Ancient Dragon; Aug 19th, 2008 at 2:34 pm. Reason: add code tags
Thanks & Regards
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Re: problem with strtok()

 
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  #2
Aug 19th, 2008
Maybe you could find the length of the string inbetween the commas. If it is zero then fill it with a space or newline.
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Re: problem with strtok()

 
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  #3
Aug 19th, 2008
strtok ignores empty fields. Edward would recommend using another solution, like strcspn and some method of reading or copying a substring:
c Syntax (Toggle Plain Text) 
  1. #include <stdio.h>
  2. #include <string.h>
  3.  
  4. int main()
  5. {
  6.   const char *str = "source,desti,string1,,string3";
  7.   const char *delims = ",";
  8.  
  9.   size_t start = 0;
  10.  
  11.   while (str[start] != '\0') {
  12.     size_t end = strcspn(str + start, delims);
  13.  
  14.     printf("%.*s\n", end, str + start);
  15.  
  16.     start += (str[start + end] != '\0') ? end + 1 : end;
  17.   }
  18. }
The benefit of this approach is that you don't modify the original string anymore, so it works with string literals.
If at first you don't succeed, keep on sucking until you do succeed.
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Re: problem with strtok()

 
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  #4
Aug 20th, 2008
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Originally Posted by Radical Edward View Post
strtok ignores empty fields. Edward would recommend using another solution, like strcspn and some method of reading or copying a substring:
c Syntax (Toggle Plain Text) 
  1. #include <stdio.h>
  2. #include <string.h>
  3.  
  4. int main()
  5. {
  6.   const char *str = "source,desti,string1,,string3";
  7.   const char *delims = ",";
  8.  
  9.   size_t start = 0;
  10.  
  11.   while (str[start] != '\0') {
  12.     size_t end = strcspn(str + start, delims);
  13.  
  14.     printf("%.*s\n", end, str + start);
  15.  
  16.     start += (str[start + end] != '\0') ? end + 1 : end;
  17.   }
  18. }
The benefit of this approach is that you don't modify the original string anymore, so it works with string literals.
Thanks a lot It was very helpful
Thanks & Regards
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  #5
2 Days Ago
Hi guys, I'm new to C here. How do I assign the value to a variable printed from the line:

C Syntax (Toggle Plain Text) 
  1. printf("%.*s\n", end, str + start);

Please advise, thanks!
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