problem with strtok()

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problem with strtok()

 
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  #1
Aug 19th, 2008
Hi All,

I am facing a problem with using the function strtok(). Following is just a sample code.
The code below stores the string str delimited by comma into an array.

I want to modify the code below so that array would contain an empty space/new line if a value is missing.

i.e., if str[] = source, desti, string1,,string3 ; then my array should hold an empty space/ new line in place of string2.

Can somebody help me with this?
Thanks in Advance

c Syntax (Toggle Plain Text) 
  1. #include <stdio.h>
  2. #include <conio.h>
  3. #include <string.h>
  4.  
  5. main() 
  6. {
  7. 	char str[] = "source,desti,string1,string2,string3";
  8. 	char delims[] = ",";
  9. 	char *result = NULL;
  10. 	char myArray[10][50],*p;
  11.  
  12.  
  13. 	result = strtok( str, delims );
  14.  
  15. 	while( result != NULL ) 
  16. 	{
  17. 		printf( "%s \n", result );
  18. 		result = strtok( NULL, delims );
  19. 	}
  20.  
  21.        getch();
  22.  
  23. }
Last edited by Ancient Dragon; Aug 19th, 2008 at 2:34 pm. Reason: add code tags
Thanks & Regards
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Re: problem with strtok()

 
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  #2
Aug 19th, 2008
Maybe you could find the length of the string inbetween the commas. If it is zero then fill it with a space or newline.
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Re: problem with strtok()

 
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  #3
Aug 19th, 2008
strtok ignores empty fields. Edward would recommend using another solution, like strcspn and some method of reading or copying a substring:
c Syntax (Toggle Plain Text) 
  1. #include <stdio.h>
  2. #include <string.h>
  3.  
  4. int main()
  5. {
  6.   const char *str = "source,desti,string1,,string3";
  7.   const char *delims = ",";
  8.  
  9.   size_t start = 0;
  10.  
  11.   while (str[start] != '\0') {
  12.     size_t end = strcspn(str + start, delims);
  13.  
  14.     printf("%.*s\n", end, str + start);
  15.  
  16.     start += (str[start + end] != '\0') ? end + 1 : end;
  17.   }
  18. }
The benefit of this approach is that you don't modify the original string anymore, so it works with string literals.
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Re: problem with strtok()

 
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  #4
Aug 20th, 2008
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Originally Posted by Radical Edward View Post
strtok ignores empty fields. Edward would recommend using another solution, like strcspn and some method of reading or copying a substring:
c Syntax (Toggle Plain Text) 
  1. #include <stdio.h>
  2. #include <string.h>
  3.  
  4. int main()
  5. {
  6.   const char *str = "source,desti,string1,,string3";
  7.   const char *delims = ",";
  8.  
  9.   size_t start = 0;
  10.  
  11.   while (str[start] != '\0') {
  12.     size_t end = strcspn(str + start, delims);
  13.  
  14.     printf("%.*s\n", end, str + start);
  15.  
  16.     start += (str[start + end] != '\0') ? end + 1 : end;
  17.   }
  18. }
The benefit of this approach is that you don't modify the original string anymore, so it works with string literals.
Thanks a lot It was very helpful
Thanks & Regards
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  #5
22 Days Ago
Hi guys, I'm new to C here. How do I assign the value to a variable printed from the line:

C Syntax (Toggle Plain Text) 
  1. printf("%.*s\n", end, str + start);

Please advise, thanks!
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