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PHP Parse error: syntax error, unexpected T_VARIABLE

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srisree

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PHP Parse error: syntax error, unexpected T_VARIABLE

Sep 24th, 2008

Hello

PHP Parse error: syntax error, unexpected T_VARIABLE in /home/mysite/public_html/guestbook/getdrawings.php on line 1

 Help with Code Tags 
 PHP Syntax (Toggle Plain Text) 
<?php
 
$dir=opendir("data");
	while ($file=readdir($dir)){
		if(substr($file, -3) == "xml"){
						print 'data/'.$file.'|';
		}
	}
	closedir($dir);
?>
<?php

$dir=opendir("data");
	while ($file=readdir($dir)){
		if(substr($file, -3) == "xml"){
						print 'data/'.$file.'|';
		}
	}
	closedir($dir);
?>

Need your suggestions to solve this problom

regards

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Re: PHP Parse error: syntax error, unexpected T_VARIABLE

Sep 24th, 2008

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PHP Parse error: syntax error, unexpected T_VARIABLE in /home/mysite/public_html/guestbook/getdrawings.php on line 1

I have tested the provided code both as it currently is and with many different modifications and from what I have found, although with single character changes errors can be made, I don't think that with this code alone that a T_variable error could occure. Especially with line 1 being

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<?php

The only possible error I could see on line one (if you have an odd server) is removing the letters

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php

from line 1. Other than that I would say that a global variable such as ini settings may be interfering with the script.
So basically I just couldn't reproduce the error and was working for me fine.

Try not to bump 10 year old threads as it can be really annoying.
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Re: PHP Parse error: syntax error, unexpected T_VARIABLE

Sep 24th, 2008

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Hello

PHP Parse error: syntax error, unexpected T_VARIABLE in /home/mysite/public_html/guestbook/getdrawings.php on line 1

Dear sisree,

I try this script but show no error.
can u give me php.ini and server details

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Re: PHP Parse error: syntax error, unexpected T_VARIABLE

Sep 24th, 2008

I think there is problem in the directory path once check that if its ok ignore this

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Re: PHP Parse error: syntax error, unexpected T_VARIABLE

Sep 24th, 2008

Hello ! I try this script too, and it works very well ! I think the probleme is out there !

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Re: PHP Parse error: syntax error, unexpected T_VARIABLE

Aug 21st, 2009

$connection = mysql_connect($host,$usernamee,$passwordd) or die ('Could not connect to server.');
$db = mysql_select_db($database,$connection) or die ('Could not select database.');
$sqlerror = mysql_error();

//The next line is where the error is, please help me out....
$sqlinsert = "INSERT INTO usercomments(namee, emailaddress, comments, datesent) VALUES ('".$fName."', '".$emaill."', '".$commentt."', '"$datee."')";

$sqlinsertt = mysql_query($sqlinsert) or die ('Could not insert record');

if($sqlinsertt)
{
echo ' RECORD INSERTED SUCCESSFULLY ';
}

else
{
echo ' Record cannot be inserted with Shipper Login: ';
//echo 'error$sqlerror';
}

?>

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Re: PHP Parse error: syntax error, unexpected T_VARIABLE

Aug 21st, 2009

•

Originally Posted by olammieConcept

$connection = mysql_connect($host,$usernamee,$passwordd) or die ('Could not connect to server.');
$db = mysql_select_db($database,$connection) or die ('Could not select database.');
$sqlerror = mysql_error();

//The next line is where the error is, please help me out....
$sqlinsert = "INSERT INTO usercomments(namee, emailaddress, comments, datesent) VALUES ('".$fName."', '".$emaill."', '".$commentt."', '"$datee."')";

$sqlinsertt = mysql_query($sqlinsert) or die ('Could not insert record');

if($sqlinsertt)
{
echo ' RECORD INSERTED SUCCESSFULLY ';
}

else
{
echo ' Record cannot be inserted with Shipper Login: ';
//echo 'error$sqlerror';
}

?>

First of all welcome to daniweb.
And did you not read my signature saying not to bump old topics. Also please use code tags as they can make it easier to read your post. As for your question, the following code should do the trick:

 Help with Code Tags 
 php Syntax (Toggle Plain Text) 
$connection = mysql_connect($host,$usernamee,$passwordd) or die ('Could not connect to server.'); 
$db = mysql_select_db($database,$connection) or die ('Could not select database.');
$sqlerror = mysql_error();
 
$fName=mysql_real_escape_string($fName);
$emaill=mysql_real_escape_string($emaill);
$commentt=mysql_real_escape_string($commentt);
$datee=mysql_real_escape_string($datee);
$sqlinsert = "INSERT INTO usercomments(namee, emailaddress, comments, datesent) VALUES ('$fName', '$emaill', '$commentt', '$datee')";
 
$sqlinsertt = mysql_query($sqlinsert) or die ('Could not insert record'); 
 
if($sqlinsertt)
{
echo '<br><br>RECORD INSERTED SUCCESSFULLY <br>';
}
 
else
{
echo '<br>Record cannot be inserted with Shipper Login:<br> ';
//echo 'error$sqlerror';
}
 
?>
$connection = mysql_connect($host,$usernamee,$passwordd) or die ('Could not connect to server.'); 
$db = mysql_select_db($database,$connection) or die ('Could not select database.');
$sqlerror = mysql_error();

$fName=mysql_real_escape_string($fName);
$emaill=mysql_real_escape_string($emaill);
$commentt=mysql_real_escape_string($commentt);
$datee=mysql_real_escape_string($datee);
$sqlinsert = "INSERT INTO usercomments(namee, emailaddress, comments, datesent) VALUES ('$fName', '$emaill', '$commentt', '$datee')";

$sqlinsertt = mysql_query($sqlinsert) or die ('Could not insert record'); 

if($sqlinsertt)
{
echo '<br><br>RECORD INSERTED SUCCESSFULLY <br>';
}

else
{
echo '<br>Record cannot be inserted with Shipper Login:<br> ';
//echo 'error$sqlerror';
}

?>

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Re: PHP Parse error: syntax error, unexpected T_VARIABLE

Aug 22nd, 2009

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Originally Posted by srisree

Hello

PHP Parse error: syntax error, unexpected T_VARIABLE in /home/mysite/public_html/guestbook/getdrawings.php on line 1
Help with Code Tags

PHP Syntax (Toggle Plain Text)
<?php
 
$dir=opendir("data");
	while ($file=readdir($dir)){
		if(substr($file, -3) == "xml"){
						print 'data/'.$file.'|';
		}
	}
	closedir($dir);
?>
<?php $dir=opendir("data"); while ($file=readdir($dir)){ if(substr($file, -3) == "xml"){ print 'data/'.$file.'|'; } } closedir($dir); ?>
Need your suggestions to solve this problom

regards

try to use getcwd.

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 PHP Syntax (Toggle Plain Text) 
 
$dirPath = getcwd();  Gets the current working directory
$thePath = $dirPath.'/data/';
$dir=opendir($thePath);
$dirPath = getcwd();  Gets the current working directory
$thePath = $dirPath.'/data/';
$dir=opendir($thePath);