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Vector Dimensions
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Join Date: Jun 2008
Posts: 973
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Solved Threads: 108
Posting Shark
Correct me if I'm wrong, but doesn't the cavet ^ symbol in C++.NET mean that the type is actually a pointer?
looks fishy... Vec1 is a pointer-type, so doesn't that mean you need to call gcnew to properly instantiate that Vec? O_O
I'd assume.
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c++ Syntax (Toggle Plain Text)
Last edited by Alex Edwards; Sep 29th, 2008 at 11:07 pm.
When using pointers in .NET, you do use * and & to address pointers so the cavet ^ symbol should only meen a type as int and double I beleive like string for the std:: and then String^ for managed.
If I put gcnew before Vec1 in the code below the compiler says this message:
'Vec1' : cannot use this type as argument of 'gcnew'
If I put gcnew before Vec1 in the code below the compiler says this message:
'Vec1' : cannot use this type as argument of 'gcnew'
typedef List<String^>^ Vec1;
typedef List<Vec1> Vec2;
Vec2 List1;
for( int j = 0; j < 1000; j++ )
{
List1.Add(gcnew Vec1());
for( int i = 0; i < 1000; i++ )
{
List1[j]->Add("0");
}
} •
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Join Date: Nov 2007
Posts: 1,294
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Solved Threads: 267
I think you are after ...
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When compiling the below code I will have a compileerror that says:
String3D : illegal use of this type as an expression
String2D : illegal use of this type as an expression
String1D : illegal use of this type as an expression
I wonder if I doing this correct when trying to iterate through all 3 Dimension with .Count ?
String3D : illegal use of this type as an expression
String2D : illegal use of this type as an expression
String1D : illegal use of this type as an expression
I wonder if I doing this correct when trying to iterate through all 3 Dimension with .Count ?
typedef List<String^> String1D;
typedef List<String1D^> String2D;
typedef List<String2D^> String3D;
String3D Dimensions;
int count1 = 0;
int count2 = -1;
for( int i = 0; i < 5; i++ )
{
if( i == 0 )
{
Dimensions.Add(gcnew String2D());
}
if( i >= 0 && i <= 4 )
{
count2 = count2 + 1;
Dimensions[count1]->Add(gcnew String1D());
}
Dimensions[count1][count2]->Add("TextString");
}
for(int h = 0; h < String3D.Count; ++h)
{
for(int j = 0; j < String2D.Count; ++j)
{
for(int k = 0; k < String1D.Count; ++k)
{
}}} Last edited by Jennifer84; Oct 2nd, 2008 at 3:01 pm.
I found out that "()" was needed. When iterating through the dimensions to show the "TextString" that was put into the List(Dimensions), only 1 MessageBox will appear.
As I have put "TextString" to 5 elements it should be 5 Times.
I am putting the string to these elements:
Dimensions[0][0][0];
Dimensions[0][1][0];
Dimensions[0][2][0];
Dimensions[0][3][0];
Dimensions[0][4][0];
As I have put "TextString" to 5 elements it should be 5 Times.
I am putting the string to these elements:
Dimensions[0][0][0];
Dimensions[0][1][0];
Dimensions[0][2][0];
Dimensions[0][3][0];
Dimensions[0][4][0];
typedef List<String^> String1D;
typedef List<String1D^> String2D;
typedef List<String2D^> String3D;
String3D Dimensions;
int count1 = 0;
int count2 = -1;
for( int i = 0; i < 5; i++ )
{
if( i == 0 )
{
Dimensions.Add(gcnew String2D());
}
if( i >= 0 && i <= 4 )
{
count2 = count2 + 1;
Dimensions[count1]->Add(gcnew String1D());
}
Dimensions[count1][count2]->Add("TextString");
}
for(int h = 0; h < String3D().Count + 1; ++h)
{
for(int j = 0; j < String2D().Count + 1; ++j)
{
for(int k = 0; k < String1D().Count + 1; ++k)
{
MessageBox::Show(Dimensions[h][j][k]);
}
}} Last edited by Jennifer84; Oct 2nd, 2008 at 3:31 pm.
What I try to find, is the equavilent to the vector ::iterator for the first code.
The first code iterates each Dimension from .begin() to the .end() and then continues
to next dimension for the 3 Dimensions.
As all these Dimensions below for "List" have been ->Add and therefore have different many elements for each Dimension, I am looking for the same(equavilent) method to Iterate each Dimension to the end as the above approach for the std::vector.
Something might be missing in the below code.
The first code iterates each Dimension from .begin() to the .end() and then continues
to next dimension for the 3 Dimensions.
C++ Syntax (Toggle Plain Text)
As all these Dimensions below for "List" have been ->Add and therefore have different many elements for each Dimension, I am looking for the same(equavilent) method to Iterate each Dimension to the end as the above approach for the std::vector.
Something might be missing in the below code.
C++ Syntax (Toggle Plain Text)
Last edited by Jennifer84; Oct 2nd, 2008 at 6:03 pm.
In some way it is needed to refer to the previous vectordimension.
The problem is that I dont know how you refer to the previous dimension beginning and end and set this to some sort of an iterator as this is put ?
String2D::iterator j = i->begin(); j != i->end(); ++j
For the List, I cant find either a begin or end member or iterator.
The below code could be a step closer perheps.
Any idéas or tips would be of help. I am quite stuck.
The problem is that I dont know how you refer to the previous dimension beginning and end and set this to some sort of an iterator as this is put ?
String2D::iterator j = i->begin(); j != i->end(); ++j
For the List, I cant find either a begin or end member or iterator.
The below code could be a step closer perheps.
Any idéas or tips would be of help. I am quite stuck.
C++ Syntax (Toggle Plain Text)
Last edited by Jennifer84; Oct 3rd, 2008 at 8:40 am.
About this thread starting question: look at my posts in solved threads (two month ago):
http://www.daniweb.com/forums/thread136351.html
http://www.daniweb.com/forums/thread137814.html
http://www.daniweb.com/forums/thread136351.html
http://www.daniweb.com/forums/thread137814.html
Last edited by ArkM; Oct 3rd, 2008 at 11:44 am.
Yes, this was the thread I was reading on but I missed it and as I saw it was as simple as this. I was imagining me something different.
It helped alot. Great !
It helped alot. Great !
C++ Syntax (Toggle Plain Text)
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Originally Posted by ArkM 
About this thread starting question: look at my posts in solved threads (two month ago):
http://www.daniweb.com/forums/thread136351.html
http://www.daniweb.com/forums/thread137814.html
Last edited by Jennifer84; Oct 3rd, 2008 at 12:44 pm.
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