DaniWeb Forum Index > Software Development > C++

Trouble with loops - Calculate sum of even and odd integers

Please support our C++ advertiser: Programming Forums - DaniWeb Sister Site

•

Join Date: Sep 2008

Posts: 21

Reputation: ShadowOfBlood is an unknown quantity at this point

Solved Threads: 0

ShadowOfBlood ShadowOfBlood is offline

Offline

Newbie Poster

Trouble with loops - Calculate sum of even and odd integers

Oct 6th, 2008

As a homework assignment, I was asked to write a program in C++ that calculates the sum of the even and odd integers in a list of integers given by the user. I think I'm on the right track, but I can't seem to get my loop right. Here's what I have so far:

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
#include <iostream>
#include <cmath>
 
using namespace std;
 
int main()
{
	int num=0, even=0, odd=0, i = 0;
	char stop = 'a';
 
    cout << "Enter a list of integers followed by the '$' sign: " << endl;                 
    cin >> num;
	stop = num;
 
		while(stop != '$')
		{
			if(num % 2 == 0) //If the number is even
				even = even + num; //Add it to the current sum of even integers
			else if(num % 2 != 0) //if the number is odd
				odd = odd + num; //Add it to the current sum of odd integers
			else
			{
				i = 1; //Otherwise, make i equal to 1
			}
 
			cin >> num;
			stop = num;
		}
 
	if(i == 1)
		cout << "Please enter only integers" << endl;
	else if(i == 0)
	{
		cout << "The sum of the even integers is: " << even << endl;
		cout << "The sum of the odd integers is: " << odd << endl;
	}
 
	return 0;
}
#include <iostream>
#include <cmath>

using namespace std;

int main()
{
	int num=0, even=0, odd=0, i = 0;
	char stop = 'a';

    cout << "Enter a list of integers followed by the '$' sign: " << endl;                 
    cin >> num;
	stop = num;

		while(stop != '$')
		{
			if(num % 2 == 0) //If the number is even
				even = even + num; //Add it to the current sum of even integers
			else if(num % 2 != 0) //if the number is odd
				odd = odd + num; //Add it to the current sum of odd integers
			else
			{
				i = 1; //Otherwise, make i equal to 1
			}

			cin >> num;
			stop = num;
		}

	if(i == 1)
		cout << "Please enter only integers" << endl;
	else if(i == 0)
	{
		cout << "The sum of the even integers is: " << even << endl;
		cout << "The sum of the odd integers is: " << odd << endl;
	}

	return 0;
}

Thanks for the help

Last edited by ShadowOfBlood; Oct 6th, 2008 at 3:43 am.

•

Join Date: Oct 2008

Posts: 118

Reputation: chococrack is on a distinguished road

Solved Threads: 14

chococrack chococrack is offline

Offline

Junior Poster

Re: Trouble with loops - Calculate sum of even and odd integers

Oct 6th, 2008

Look at line 13

Help with Code Tags

C++ Syntax (Toggle Plain Text)

 stop = num;

Now ask yourself, "self, whats stop?"
"a character."
"self, whats num?"
"an integer."

Whats probably going down is that the the char (stop) is being assigned an integer, which in effect is tossing your loop off.

Are you only interested in positive integers? Because then you could ask for a negative value to terminate that list of integers.

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
while(num != -1)
while(num != -1)

Last edited by chococrack; Oct 6th, 2008 at 3:54 am.

I would love to change the world, but they won't give me the source code

•

Join Date: Sep 2008

Posts: 21

Reputation: ShadowOfBlood is an unknown quantity at this point

Solved Threads: 0

ShadowOfBlood ShadowOfBlood is offline

Offline

Newbie Poster

Re: Trouble with loops - Calculate sum of even and odd integers

Oct 6th, 2008

The question states: Write a program that reads a set of integers, and then finds and prints the sum of the even and odd integers.

I'm assuming it means positive and negative integers. Any ideas?

•

Join Date: Sep 2008

Posts: 21

Reputation: ShadowOfBlood is an unknown quantity at this point

Solved Threads: 0

ShadowOfBlood ShadowOfBlood is offline

Offline

Newbie Poster

Re: Trouble with loops - Calculate sum of even and odd integers

Oct 6th, 2008

Nvm, I was going about it wrong. I figured it out. Here's what I have:

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
#include <iostream>
#include <cmath>
 
using namespace std;
 
int main()
{
	int even = 0, odd = 0, dig, num;
 
	cout << "Please enter a list of numbers (ex. - 12345)" << endl;
	cin >> num;
 
	while (num > 0)
	{
		dig = num % 10;
		num = num / 10;
 
		if(dig % 2 == 0)
			even = even + dig;
		else
			odd = odd + dig;
	}
 
	cout << "The sum of the even integers is: " << even << endl;
	cout << "The sum of the odd integers is: " << odd << endl;
 
	return 0;
}
#include <iostream>
#include <cmath>

using namespace std;

int main()
{
	int even = 0, odd = 0, dig, num;

	cout << "Please enter a list of numbers (ex. - 12345)" << endl;
	cin >> num;

	while (num > 0)
	{
		dig = num % 10;
		num = num / 10;
		
		if(dig % 2 == 0)
			even = even + dig;
		else
			odd = odd + dig;
	}

	cout << "The sum of the even integers is: " << even << endl;
	cout << "The sum of the odd integers is: " << odd << endl;

	return 0;
}

Thanks for the help

•

Join Date: Mar 2008

Posts: 678

Reputation: Sky Diploma is a splendid one to behold

Solved Threads: 101

Sky Diploma Sky Diploma is offline

Offline

Practically a Master Poster

Re: Trouble with loops - Calculate sum of even and odd integers

Oct 6th, 2008

Dont You Think it is giving you the wrong answer?

1. Please Mark Your Thread as Solved After Getting Your Answers.
2. Please Use CODE TAGS .

•

Join Date: Sep 2008

Posts: 21

Reputation: ShadowOfBlood is an unknown quantity at this point

Solved Threads: 0

ShadowOfBlood ShadowOfBlood is offline

Offline

Newbie Poster

Re: Trouble with loops - Calculate sum of even and odd integers

Oct 6th, 2008

It was giving me right answers when I checked it O.o

Is something wrong with it?

•

Join Date: Mar 2008

Posts: 89

Reputation: bhoot_jb is on a distinguished road

Solved Threads: 2

bhoot_jb

Offline

Junior Poster in Training

Re: Trouble with loops - Calculate sum of even and odd integers

Oct 6th, 2008

•

Originally Posted by ShadowOfBlood

Nvm, I was going about it wrong. I figured it out. Here's what I have:
Help with Code Tags

C++ Syntax (Toggle Plain Text)
#include <iostream>
#include <cmath>
 
using namespace std;
 
int main()
{
	int even = 0, odd = 0, dig, num;
 
	cout << "Please enter a list of numbers (ex. - 12345)" << endl;
	cin >> num;
 
	while (num > 0)
	{
		dig = num % 10;
		num = num / 10;
 
		if(dig % 2 == 0)
			even = even + dig;
		else
			odd = odd + dig;
	}
 
	cout << "The sum of the even integers is: " << even << endl;
	cout << "The sum of the odd integers is: " << odd << endl;
 
	return 0;
}
#include <iostream> #include <cmath> using namespace std; int main() { int even = 0, odd = 0, dig, num; cout << "Please enter a list of numbers (ex. - 12345)" << endl; cin >> num; while (num > 0) { dig = num % 10; num = num / 10; if(dig % 2 == 0) even = even + dig; else odd = odd + dig; } cout << "The sum of the even integers is: " << even << endl; cout << "The sum of the odd integers is: " << odd << endl; return 0; }
Thanks for the help

what is quite confusing is the 'num' integer.
You said that you are taking input of a list of integers while you have just asked for a single integer.
I assume that you have taken the input of "list of integers" in a single integer 'num' itself, i.e., you have considered the value of 'num' as a list of integers (digit by digit)

if this is what you have assumed, i think this is a wrong approach. You would have rather used an array.

Think upon it.

Bhoot

•

Join Date: Oct 2008

Posts: 118

Reputation: chococrack is on a distinguished road

Solved Threads: 14

chococrack chococrack is offline

Offline

Junior Poster

Re: Trouble with loops - Calculate sum of even and odd integers

Oct 6th, 2008

 Help with Code Tags 
 C++ Syntax (Toggle Plain Text) 
#include <iostream>
#include <cmath>
 
using namespace std;
 
int main()
{
	int even = 0, odd = 0, dig, num;
 
	cout << "Please enter a list of numbers (-7777 to terminate)" << endl;
	cin >> num;
 
	while (num != -7777)  // off the wall check value
	{
 
		// dig = num % 10;
		// num = num / 10;           <--- what are these for?
 
 
 
		if(dig % 2 == 0)       // if the number is even
			even += num; // add it to the previous even sum						
		else
			odd += num;   // otherwise add it to the odd sum
 
		cout << "Enter next number: ";
		cin >> num;
	}
 
	cout << "The sum of the even integers is: " << even << endl;
	cout << "The sum of the odd integers is: " << odd << endl;
 
	return 0;
}
#include <iostream>
#include <cmath>

using namespace std;

int main()
{
	int even = 0, odd = 0, dig, num;

	cout << "Please enter a list of numbers (-7777 to terminate)" << endl;
	cin >> num;

	while (num != -7777)  // off the wall check value
	{
		
		// dig = num % 10;
		// num = num / 10;           <--- what are these for?


		
		if(dig % 2 == 0)       // if the number is even
			even += num; // add it to the previous even sum						
		else
			odd += num;   // otherwise add it to the odd sum

		cout << "Enter next number: ";
		cin >> num;
	}

	cout << "The sum of the even integers is: " << even << endl;
	cout << "The sum of the odd integers is: " << odd << endl;

	return 0;
}