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creating a method for texts

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Join Date: Nov 2007

Posts: 18

Reputation: enuff4life is an unknown quantity at this point

Solved Threads: 0

enuff4life enuff4life is offline

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Newbie Poster

creating a method for texts

Nov 11th, 2008

I need to creat a method something like... when the user inputs

test1
test2 haha

test3
end

and display that should contain exact same one as above except "end":
test1
test2 haha

test3

so the "end" is the keyword to finish the inputing...

 Help with Code Tags 
 Java Syntax (Toggle Plain Text) 
                    String s = new String("");
		String s1 = new String("");
		System.out.println("enter String : ");
		Scanner keyboard = new Scanner(System.in);
 
		while(!s.equals("end")){
			s = keyboard.nextLine();
			s1 += s + "\n"; 
 
		}
		System.out.println("you've typed: \n");
		System.out.println(s1);
                    String s = new String("");
		String s1 = new String("");
		System.out.println("enter String : ");
		Scanner keyboard = new Scanner(System.in);
		
		while(!s.equals("end")){
			s = keyboard.nextLine();
			s1 += s + "\n"; 
		
		}
		System.out.println("you've typed: \n");
		System.out.println(s1);

oh I've just figured out. however, i see see the "end". how do i remove it?

Last edited by enuff4life; Nov 11th, 2008 at 4:53 pm.

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Join Date: Jun 2007

Posts: 59

Reputation: Chaster is an unknown quantity at this point

Solved Threads: 3

Chaster

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Junior Poster in Training

Re: creating a method for texts

Nov 11th, 2008

 Help with Code Tags 
 Java Syntax (Toggle Plain Text) 
                    String s = new String("");
		String s1 = new String("");
		System.out.println("enter String : ");
		Scanner keyboard = new Scanner(System.in);
 
		while(!s.equals("end")){
			s = keyboard.next();
			s1 += s+" ";
                       // or s1 += s+"/n";
 
		}
 
 
		System.out.println("you've typed: \n");
		System.out.println(s1);
                    String s = new String("");
		String s1 = new String("");
		System.out.println("enter String : ");
		Scanner keyboard = new Scanner(System.in);
		
		while(!s.equals("end")){
			s = keyboard.next();
			s1 += s+" ";
                       // or s1 += s+"/n";
		
		}
		

		System.out.println("you've typed: \n");
		System.out.println(s1);

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Join Date: Dec 2007

Posts: 1,677

Reputation: javaAddict is a name known to all

Solved Threads: 226

javaAddict javaAddict is offline

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Posting Virtuoso

Re: creating a method for texts

Nov 12th, 2008

•

Originally Posted by Chaster

Help with Code Tags

Java Syntax (Toggle Plain Text)
                    String s = new String("");
		String s1 = new String("");
		System.out.println("enter String : ");
		Scanner keyboard = new Scanner(System.in);
 
		while(!s.equals("end")){
			s = keyboard.next();
			s1 += s+" ";
                       // or s1 += s+"/n";
 
		}
 
 
		System.out.println("you've typed: \n");
		System.out.println(s1);
String s = new String(""); String s1 = new String(""); System.out.println("enter String : "); Scanner keyboard = new Scanner(System.in); while(!s.equals("end")){ s = keyboard.next(); s1 += s+" "; // or s1 += s+"/n"; } System.out.println("you've typed: \n"); System.out.println(s1);

That is not what enuff4life has asked. Try this:

 Help with Code Tags 
 Java Syntax (Toggle Plain Text) 
                    String s = new String("");
		String s1 = new String("");
		System.out.println("enter String : ");
		Scanner keyboard = new Scanner(System.in);
 
		while(!s.equals("end")){
			s = keyboard.nextLine();
 
                       if (!s.equals("end")) {
                             s1 += s + "\n"; 
                       }
		}
		System.out.println("you've typed: \n");
		System.out.println(s1);
                    String s = new String("");
		String s1 = new String("");
		System.out.println("enter String : ");
		Scanner keyboard = new Scanner(System.in);
		
		while(!s.equals("end")){
			s = keyboard.nextLine();

                       if (!s.equals("end")) {
                             s1 += s + "\n"; 
                       }
		}
		System.out.println("you've typed: \n");
		System.out.println(s1);

Or keep the while-loop as it is and use the methods:
String.indexOf()
and
String.subString()

 Help with Code Tags 
 Java Syntax (Toggle Plain Text) 
int index = s1.indexOf("end");
System.out.println(s1.subString(0,index));
int index = s1.indexOf("end");
System.out.println(s1.subString(0,index));

Link for the String class.

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Join Date: Jan 2007

Posts: 706

Reputation: stultuske is a jewel in the rough

Solved Threads: 84

stultuske

Offline

Master Poster

Re: creating a method for texts

Nov 12th, 2008

•

Originally Posted by javaAddict

That is not what enuff4life has asked. Try this:
Help with Code Tags

Java Syntax (Toggle Plain Text)
                    String s = new String("");
		String s1 = new String("");
		System.out.println("enter String : ");
		Scanner keyboard = new Scanner(System.in);
 
		while(!s.equals("end")){
			s = keyboard.nextLine();
 
                       if (!s.equals("end")) {
                             s1 += s + "\n"; 
                       }
		}
		System.out.println("you've typed: \n");
		System.out.println(s1);
String s = new String(""); String s1 = new String(""); System.out.println("enter String : "); Scanner keyboard = new Scanner(System.in); while(!s.equals("end")){ s = keyboard.nextLine(); if (!s.equals("end")) { s1 += s + "\n"; } } System.out.println("you've typed: \n"); System.out.println(s1);

or this way:

 Help with Code Tags 
 Java Syntax (Toggle Plain Text) 
              String s = new String("");
		String s1 = new String("");
		System.out.println("enter String : ");
		Scanner keyboard = new Scanner(System.in);
		s = keyboard.nextLine();
		while(!s.equals("end")){
			s1 += s + "\n"; 
                        s = keyboard.nextLine();
		}
		System.out.println("you've typed: \n");
		System.out.println(s1);
              String s = new String("");
		String s1 = new String("");
		System.out.println("enter String : ");
		Scanner keyboard = new Scanner(System.in);
		s = keyboard.nextLine();
		while(!s.equals("end")){
			s1 += s + "\n"; 
                        s = keyboard.nextLine();
		}
		System.out.println("you've typed: \n");
		System.out.println(s1);