help with C++ program

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help with C++ program

 
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  #1
Nov 12th, 2008
hi guys
am a total noob with C++ and im trying to write a program that will take a user inputted integer and displays its divisors and then tell the user whether it is a perfect number or not.

So far I have
C++ Syntax (Toggle Plain Text) 
  1. #include <iostream>
  2.  
  3. using namespace std;
  4. int main() {
  5.  
  6. int n;
  7. bool devisor;
  8. cout << "enter number";
  9. cin >> n; 
  10.  
  11. for (int i = 0 ; i < n/2 ; i++ ){
  12. 	devisor = true;
  13. 	if ( n % i = 0 ){
  14. 	devisor = false;
  15. 	}
  16. }	
  17. if(devisor){
  18. 	cout << i << "is a devisor" << end1;
  19. }
  20. return 0;
  21. }
any extra help will be much appreciated
Last edited by Narue; Nov 12th, 2008 at 12:58 pm. Reason: added code tags
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Re: help with C++ program

 
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  #2
Nov 12th, 2008
What is it that you are having problem with? Are you getting errors when you compile? Does it compile but doesn't display the correct values??
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Re: help with C++ program

 
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  #3
Nov 12th, 2008
well it doesn't compile it throws out the following errors:

error C2106: '=' : left operand must be l-value
error C2065: 'i' : undeclared identifier
error C2065: 'end1' : undeclared identifier
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Re: help with C++ program

 
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  #4
Nov 12th, 2008
>error C2106: '=' : left operand must be l-value
In your code you say if ( n % i = 0 ){ . C++ uses == for equality and = for assignment, so you're using the wrong operator.

>error C2065: 'i' : undeclared identifier
This is a simple one: you haven't declared the variable i anywhere, so you can't use it.

>error C2065: 'end1' : undeclared identifier
This is also simple, and probably due to poor choice of fonts in your text editor. It's endl with a lower case L, not the number 1. Think of endl as standing for "end line" and you shouldn't have this problem anymore.
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Re: help with C++ program

 
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  #5
Nov 12th, 2008
Taking the mod of 0 might be a problem as well, since you declare i to start at zero.
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Re: help with C++ program

 
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  #6
Nov 12th, 2008
thanks a lot guys, now it compiles correctly however wont display the divisors??

code now looks like this
C++ Syntax (Toggle Plain Text) 
  1. #include <iostream>
  2.  
  3. using namespace std;
  4. int main() {
  5.  
  6. int i;
  7. int n;
  8. bool devisor;
  9. cout << "enter number" <<endl;
  10. cin >> n; 
  11.  
  12. for (int i = 1 ; i < n/2 ; i++ ){
  13. 	devisor = true;
  14. 	if ( n % i == 0 ){
  15. 	devisor = false;
  16. 	}
  17. }	
  18. if(devisor){
  19. 	cout << i << "is a devisor" << endl;
  20. }
  21. return 0;
  22. }
i know im in the realms of retardation to you guys but help is a godsend!
Last edited by Narue; Nov 12th, 2008 at 3:21 pm. Reason: added code tags, please do it yourself next time
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Re: help with C++ program

 
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  #7
Nov 12th, 2008
can you try this...

C++ Syntax (Toggle Plain Text) 
  1. if(devisor==true)
  2. {
  3. cout << i << "is a devisor" << endl;
  4. }
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Re: help with C++ program

 
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  #8
Nov 12th, 2008
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Originally Posted by AcidG3rm5 View Post
can you try this...
C++ Syntax (Toggle Plain Text) 
  1. if(devisor==true)
  2. {
  3. cout << i << "is a devisor" << endl;
  4. }
Yes, it's the same thing. Since if() checks if the statement is true.
When you say if(condition == false) you're asking, "if it is true that this condition is equivalent to false".
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