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Sending "char" to "int" variable

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salman213

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Sending "char" to "int" variable

Nov 19th, 2008

Hi i have a question. Im using Dev C++ and this simple program takes in values of x and outputs *prints them on the screen. Although x should be an integer If i put in for example the letter "u" or any letter for that matter it goes on and on without asking me for anohter input and uses the last input on the screen. Why?

 Help with Code Tags 
 C Syntax (Toggle Plain Text) 
#include <iostream>
#include <stdio.h>
using namespace std;
main()
{
int x=0;
while (true)
{
scanf("%d",&x); 
printf("%d", x);
}
 
}
#include <iostream>
#include <stdio.h>
using namespace std;
main()
{
int x=0;
while (true)
{
scanf("%d",&x); 
printf("%d", x);
}

}

Last edited by salman213; Nov 19th, 2008 at 10:12 pm.

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gautam610

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Re: Sending "char" to "int" variable

Nov 20th, 2008

since you declare x as an integer so system allocate 2 byte for this variable & when u give input as character it converts into an integer through ASCII value & print that one.............

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mahlerfive mahlerfive is offline

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Re: Sending "char" to "int" variable

Nov 20th, 2008

The above poster is not exactly correct.

When you call scanf(), if the function fails (which will happen when you try to read an integer but it is given a character), it will not actually consume the input character from the input. This means the next time you call scanf() it will end up trying to read the same character again!

To catch this, you can check the return value from scanf(). It tells you the number of inputs read successfully. When there is an error it should return less than the number of variables you wanted to read in (in this case, less than 1). If this happens, you need to flush the input stream. The easiest way to do this is just by calling fflush(stdin).

Apparently fflush() is a "bad practice", but in small programs it should be fine. There are other "better" ways to deal with this.

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MosaicFuneral MosaicFuneral is offline

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Re: Sending "char" to "int" variable

Nov 20th, 2008

If you're going to include the C++ headers, why not use cin and cout ?

"Jedenfalls bin ich überzeugt, daß der Alte nicht würfelt."
"I became very sensitive to what will happen to all this and all of us." -Two geniuses named Albert

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salman213

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Re: Sending "char" to "int" variable

Nov 20th, 2008

By the way im actually programming in C for something else thats why im using it and not Cin/cout.

AND THANKS

fflush(stdin);

seems to work,
just a question, wat is the equivalent statement in C++?

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Re: Sending "char" to "int" variable

Nov 20th, 2008

I don't believe so. No reason for one.

"Jedenfalls bin ich überzeugt, daß der Alte nicht würfelt."
"I became very sensitive to what will happen to all this and all of us." -Two geniuses named Albert

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Narue

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Re: Sending "char" to "int" variable

Nov 21st, 2008

>im actually programming in C
Then keep in mind that C89 doesn't support the <iostream> header, namespaces, or the true keyword. Your code won't compile as C, and failing to return a value from main is undefined behavior.

>wat is the equivalent statement in C++?
I thought you were programming in C.

Anyway, the equivalent statement in C++ is fflush(stdin) . It's equally broken in both languages, I strongly recommend you forget that it happens to work on your compiler. A more correct C++ solution is istream::ignore:

 Help with Code Tags 
 C Syntax (Toggle Plain Text) 
#include <iostream>
#include <ios>
#include <limits>
 
std::cin.ignore ( std::numeric_limits<std::streamsize>::max(), '\n' );
#include <iostream>
#include <ios>
#include <limits>

std::cin.ignore ( std::numeric_limits<std::streamsize>::max(), '\n' );

And the equivalent C code uses a loop:

 Help with Code Tags 
 c Syntax (Toggle Plain Text) 
#include <stdio.h>
 
int ch;
 
do
  ch = fgetc ( stdin );
while ( ch != EOF && ch != '\n' );
#include <stdio.h>

int ch;

do
  ch = fgetc ( stdin );
while ( ch != EOF && ch != '\n' );

Which can also be done in C++:

 Help with Code Tags 
 C Syntax (Toggle Plain Text) 
#include <iostream>
 
char ch;
 
do
  std::cin.get ( ch );
while ( std::cin && ch != '\n' );
#include <iostream>

char ch;

do
  std::cin.get ( ch );
while ( std::cin && ch != '\n' );