You want to sort the error array and keep the relationship with the rows in weights array ???
One way is to use another array that contains indices into both error and weights array. When you sort error array actually move the rows in this third array. Use the third array as indirect access to the other arrays.
indices[] = {0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15};
// sort errors array
for(int i = 0; i < 15; i++)
{
for(int j= i+1; j < 16; j++)
{
if( errors[ indices[i] ] < errors[ indices[j] ] )
{
int temp = indices[i];
indices[i] = indices[j];
indices[j] = temp;
}
}
}
Now to reference weights: assume variable X is an integer that contains the value from errors index
weights[ indices[x] ][0];
Or, if that is a little too complex for you, just sort both errors and weights array at the same time. When you exchange elements of errors array also exchange all columns in the corresponding rows of weights.
Last edited by Ancient Dragon; Nov 20th, 2008 at 9:04 pm.
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