View Single Post
Join Date: Jan 2008
Posts: 3,752
Reputation: VernonDozier has a reputation beyond repute VernonDozier has a reputation beyond repute VernonDozier has a reputation beyond repute VernonDozier has a reputation beyond repute VernonDozier has a reputation beyond repute VernonDozier has a reputation beyond repute VernonDozier has a reputation beyond repute VernonDozier has a reputation beyond repute VernonDozier has a reputation beyond repute VernonDozier has a reputation beyond repute VernonDozier has a reputation beyond repute 
Solved Threads: 491
Featured Poster
VernonDozier VernonDozier is offline Offline
Senior Poster

Re: How to Sum a Pascal Triangle

 
0
  #6
Dec 4th, 2008
Originally Posted by cherryteresa View Post
You're right, I was thinking about how all this math ties together. It's crazy to think about sometimes!

Okay, so thank you for pointing out the power thing. I think this is where I got stuck before. I'm trying to figure out how to raise something to the power. We didn't go over this in class and all the things I could find online showed it in printf form and not cout. And so I'm having trouble figuring out how to do it. I think basically what I need to do is:

for (int x=0; x<size; x++)
	{
		sum += pow (2, x); - // trying to figure 
                                               //  out how to 
                                               //translate this to code.
                                              // 2 to the x power

		for (int y=0; y<size; y++)
		{

		}
		cout<<sum<<"\n"<<endl;
	}
}

I'm going to keep searching.
pow (int, int) doesn't exist.

http://www.cplusplus.com/reference/c...cmath/pow.html

Make one or both a double:
  1. pow (2.0, x); // or pow (2.0, (double) x);

pow is from cmath, which you have as math.h. You may want to change those #include statements to include C++ libraries (cstdlib, cctype, cmath, cstdio) rather than the .h files. I'm not sure whether the compiler cares or not (probably not), but at least it makes clear that you are using C++ to the reader.
Reply With Quote